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Novosadov [1.4K]
3 years ago
12

Mohan is selling cookies at the economics fair. As he decides how to package the cookies, he finds that when he bags them in gro

ups of 4, he has 3 left over. When he bags them in groups of 5, he has 2 left over. When he bags them in groups of 7, he has 4 left over. What is the least number of cookies that Mohan could have
Mathematics
1 answer:
Vlad [161]3 years ago
6 0

Answer:

67 cookies

Step-by-step explanation:

When packaging in groups of 4, the possible number of cookies is x = (4n+3). The possible values are:

7, 11, 15, 19, 23, 27, 31, 35, 39, 43, 47, 51, 55, 59, 63, 67, 71...

When packaging in groups of 5, the possible number of cookies is x = (5n+2). The possible values are:

7, 12, 17, 22, 27, 32, 37, 42, 47, 52, 57, 62, 67, 72, 77...

When packaging in groups of 7, the possible number of cookies is x = (7n+4). The possible values are:

11, 18, 25, 32, 39, 46, 53, 60, 67, 74, 81, 88, 95...

The least value that appears on all three possibilities is 67, therefore the least number of cookies that Mohan could have is 67.

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