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3 years ago

9

Five comedians (Joe, Beth, Seth, Lucia and Darth) are planning a show. The order of each performance is randomly selected. How m

any different orders are possible?

2 answers:

Deffense [45]3 years ago

5 0

The five comedians should have around three

Mademuasel [1]3 years ago

3 0

The show of the five comedians should be around three

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Answer for 2,3,4 help pls thanks

Lemur [1.5K]

$(90 \times 15) \div 9 = \: is \: your \: answer$

Step-by-step explanation:

1. B is true

2 . I don't know

3.

4 0

3 years ago

4- A manufacturing process produces items whose weights are normally distributed. It is known that 22.57% of all the items produ

galben [10]

Answer:

$\\ \mu = 118\;grams\;and\;\sigma=30\;grams$

Step-by-step explanation:

We need to use z-scores and a standard normal table to find the values that corresponds to the probabilities given, and then to solve a system of equations to find $\\ \mu\;and\;\sigma$ .

<h3>First Case: items from 100 grams to the mean</h3>

For finding probabilities that corresponds to z-scores, we are going to use here a <u>Standard Normal Table </u><u><em>for cumulative probabilities from the mean </em></u><em>(Standard normal table. Cumulative from the mean (0 to Z), 2020, in Wikipedia) </em>that is, the "probability that a statistic is between 0 (the mean) and Z".

A value of a z-score for the probability P(100<x<mean) = 22.57% = 0.2257 corresponds to a value of z-score = 0.6, that is, the value is 0.6 standard deviations from the mean. Since this value is <em>below the mean</em> ("the items produced weigh between 100 grams up to the mean"), then the z-score is negative.

Then

$\\ z = -0.6\;and\;z = \frac{x-\mu}{\sigma}$

$\\ -0.6 = \frac{100-\mu}{\sigma}$ (1)

<h3>Second Case: items from the mean up to 190 grams</h3>

We can apply the same procedure as before. A value of a z-score for the probability P(mean<x<190) = 49.18% = 0.4918 corresponds to a value of z-score = 2.4, which is positive since it is after the mean.

Then

$\\ z =2.4\;and\; z = \frac{x-\mu}{\sigma}$

$\\ 2.4 = \frac{190-\mu}{\sigma}$ (2)

<h3>Solving a system of equations for values of the mean and standard deviation</h3>

Having equations (1) and (2), we can form a system of two equations and two unknowns values:

$\\ -0.6 = \frac{100-\mu}{\sigma}$ (1)

$\\ 2.4 = \frac{190-\mu}{\sigma}$ (2)

Rearranging these two equations:

$\\ -0.6*\sigma = 100-\mu$ (1)

$\\ 2.4*\sigma = 190-\mu$ (2)

To solve this system of equations, we can multiply (1) by -1, and them sum the two resulting equation:

$\\ 0.6*\sigma = -100+\mu$ (1)

$\\ 2.4*\sigma = 190-\mu$ (2)

Summing both equations, we obtain the following equation:

$\\ 3.0*\sigma = 90$

Then

$\\ \sigma = \frac{90}{3.0} = 30$

To find the value of the mean, we need to substitute the value obtained for the standard deviation in equation (2):

$\\ 2.4*30 = 190-\mu$ (2)

$\\ 2.4*30 - 190 = -\mu$

$\\ -2.4*30 + 190 = \mu$

$\\ \mu = 118$

7 0

3 years ago

A. Equilateral<br> B. Right<br> C. Obtuse<br> D. Acute<br> E. Scalene

faltersainse [42]

<u>Answer:</u>

A) Scalene E) Obtuse

<u>Detailed Explanation:</u>

A) Scalene

This triangle would be classified as scalene because none of the angles are equal.

____________________________________________________________

E) Obtuse

This triangle would be classified as an scalene triangle because one of the angles is larger than 90 degrees.

8 0

3 years ago

Read 2 more answers

You purchased concentrated cleaner that must be diluted (watered down)

abruzzese [7]

Answer:

The volume of the concentrated 80 gallons mixture is 20 gallons

The volume of water in the 80 gallons mixture is 60 gallons

Step-by-step explanation:

The given parameters are;

The content of Container A = The cleaner

The concentration of the cleaner = 20% solution

The content of Container B = Pure water

The concentration of the desired solution = 5%

The volume of the required solution = 80 gallons

Let x represent the volume of the concentrated solution and y represent the volume of water in the 80 gallons mixture

Therefore, we have;

20/100 × x + y×0 = 5/100×80

x + y = 80

y = 80 - x

20/100 × x + (80 - x)×0 = 5/100×80

0.2·x = 4

x = 4/0.2 = 20

x = 20 gallons

y = 80 - x = 80 - 20 = 60

y = 60 gallons

The volume of the concentrated solution (80 gallons mixture) = x = 20 gallons

The volume of water in the 80 gallons mixture = y = 60 gallons.

8 0

3 years ago

• Manuela has two boxes. The larger of the two boxes has dimensions of 15 cm

valkas [14]

Answer:

6500 cm^3.

Step-by-step explanation:

That would be the volume of the large box - the volume of the cube

= 15*25*20 - 10^3

= 7500 - 1000

= 6500 cm^3.

8 0

3 years ago