Answer:
there is no solution for these linear equations in two variables.
since a1 (y) = a2 (y)
b1 (5x) = b2 (5x)
but, c1 (12) not equal to c2 (18)
Yes. They are both right.
Step-by-step explanation:
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Step 1:
Wright the equation
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Step 2:
Transfer the power of y ie ¹² up to subtract it
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Step 3:
by subtracting the powers we get 0
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Step 4:
so the results comes 1 because anything ⁰=1
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⚡Final answer :1✓
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hope it helped you:)
Answer:
y = 0
Step-by-step explanation:
It is always a good idea to look at the question and make some observations about it. Here, you might observe ...
- all of the bases are powers of 3: 243 = 3^5; 9 = 3^2
- y is a factor of every exponent
The latter observation is important, because it means that when y=0, every exponential expression has a value of 1. Hence y = 0 is a solution.
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To solve the equation, you can write it in terms of powers of 3.
(3^5)^(-y) = (3^-5)^(3y)·(3^2)^(-2y)
3^(-5y) = 3^(-15y)·3^(-4y)
3^(-5y) = 3^(-19y)
-5y = -19y . . . . . . . . equating exponents; equivalent to taking log base 3
14y = 0 . . . . . . . . . . add 19y
y = 0 . . . . . . . . . . . one solution
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The rules of exponents we used are ...
(a^b)(a^c) = a^(b+c)
(a^b)^c = a^(bc)
1/a^b = a^-b
Answer:
Are u CPPS
Step-by-step explanation:
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