Given:
The three vertices of a parallelogram are (-3,8), (4,5), (2,-5).
To find:
The fourth vertex of the parallelogram.
Solution:
Let the vertices of the parallelogram are A(-3,8), B(4,5), C(2,-5) and D(a,b).
We know that, diagonals of a parallelogram bisect each other. It means midpoints of both diagonals are same.
Midpoint formula:
Two diagonals of ABCD are AC and BD.
Midpoint of AC = Midpoint of BD
On comparing both sides, we get
And,
Therefore, the coordinates of fourth vertex are (-5,-2).
Answer:
it may possible but based on the answer.
Step-by-step explanation:
Negative value is a value which is less than 0
Answer:
The average number of trials required to get the first success
Perhaps you mean "slope-intercept" form. Solve for y and reduce the fractions.
.. -8x -6 = 2y . . . . . . . . add 2y-6
.. y = -4x -3 . . . . . . . . . divide by 2
Your line in slope-intercept form is
.. y = -4x -3
Answer:
Step-by-step explanation:
Given △KMN, ABCD is a square where KN=a, MP⊥KN, MP=h.
we have to find the length of AB.
Let the side of square i.e AB is x units.
As ADCB is a square ⇒ ∠CDN=90°⇒∠CDP=90°
⇒ CP||MP||AB
In ΔMNP and ΔCND
∠NCD=∠NMP (∵ corresponding angles)
∠NDC=∠NPM (∵ corresponding angles)
By AA similarity rule, ΔMNP~ΔCND
Also, ΔKAP~ΔKPM by similarity rule as above.
Hence, corresponding sides are in proportion
Adding above two, we get
⇒ 
⇒ 
⇒ 
⇒ 
⇒ 
⇒ 
