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mario62 [17]
2 years ago
5

The radius of a circle is 9 inches. What is the circle's area? Use 3.14 for ​.

Mathematics
2 answers:
Anna007 [38]2 years ago
5 0

Answer:

<u>254.34 in²</u>

Step-by-step explanation:

<u>Area of a circle</u>

  • A = πr²
  1. <u>r = radius of the circle</u>

<u>Solving</u>

  • A = 3.14 x (9)²
  • A = 3.14 x 81
  • A = <u>254.34 in²</u>
slamgirl [31]2 years ago
5 0

Answer:

254.47 in²(rounded to nearest hundredth)

_________________________________________________________

A = \pi r^2

<em>tiny r means radius</em>

<em>² means multiply the number by itself twice</em>

<em />\pi r^2 = \pi * 9^2 = 81\pi(254.47~in^2)

_________________________________________________________

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PlZ HELP WILL MARK YOU AS THE BRAINLIEST!
defon

Answer:

1. distance = sqrt( (7-7)^2+(2- -8)^2) = 10

2.  check out desk (0,0 ) => distance = sqrt( (0- -9)^2+(0-0)^2) = 9

3. last corner ( -3, 4)

4. area = sqrt( (-10- -10)^2+(10-4)^2) x sqrt( (-3- -10)^2+(10-10)^2) = 6x7 =42

5. check desk (0,0), south direction = negative y axis => P_beginning (0,-20), P_end (0,-(20+25)) = (0,-45)

6. A(-2,-1) and B(4,-1) lie in y =-1. AB = sqrt( (-2- 4)^2+(-1- -1)^2) =6

=> area = 3.6x6 =21.6

=> peri = 2x(3.6+6) = 19.2

7. A(-5,4) and B(2,4), AB =  sqrt( (-5- 2)^2+(4- -4)^2) = 7 => AB is base

=> p = peri = 7+ 8.3x2 = 23.6

=> area = sqrt[px(p-7)x(p-8.3)x(p-8.3)]

             =sqrt[23.6x(23.6-7)x(23.6-8.3)x(23.6-8.3)] = 302.8

5 0
4 years ago
1.What are the zeros of the polynomial function?
Lorico [155]
Let's to the first example:

f(x) = x^2 + 9x + 20

Ussing the formula of basckara

a = 1
b = 9
c = 20

Delta = b^2 - 4ac

Delta = 9^2 - 4.(1).(20)

Delta = 81 - 80

Delta = 1

x = [ -b +/- √(Delta) ]/2a

Replacing the data:

x = [ -9 +/- √1 ]/2

x' = (-9 -1)/2 <=> - 5

Or

x" = (-9+1)/2 <=> - 4
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Already the second example:

f(x) = x^2 -4x -60

Ussing the formula of basckara again

a = 1
b = -4
c = -60

Delta = b^2 -4ac

Delta = (-4)^2 -4.(1).(-60)

Delta = 16 + 240

Delta = 256

Then, following:

x = [ -b +/- √(Delta)]/2a

Replacing the information

x = [ -(-4) +/- √256 ]/2

x = [ 4 +/- 16]/2

x' = (4-16)/2 <=> -6

Or

x" = (4+16)/2 <=> 10
______________

Now we are going to the 3 example

x^2 + 24 = 14x

Isolating 14x , but changing the sinal positive to negative

x^2 - 14x + 24 = 0

Now we can to apply the formula of basckara

a = 1
b = -14
c = 24

Delta = b^2 -4ac

Delta = (-14)^2 -4.(1).(24)

Delta = 196 - 96

Delta = 100

Then we stayed with:

x = [ -b +/- √Delta ]/2a

x = [ -(-14) +/- √100 ]/2

We wiil have two possibilities

x' = ( 14 -10)/2 <=> 2

Or

x" = (14 +10)/2 <=> 12
________________


To the last example will be the same thing.

f(x) = x^2 - x -72

a = 1
b = -1
c = -72

Delta = b^2 -4ac

Delta = (-1)^2 -4(1).(-72)

Delta = 1 + 288

Delta = 289

Then we are going to stay:

x = [ -b +/- √Delta]/2a

x = [ -(-1) +/- √289]/2

x = ( 1 +/- 17)/2

We will have two roots

That's :

x = (1 - 17)/2 <=> -8

Or

x = (1+17)/2 <=> 9


Well, this would be your answers.


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3 years ago
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Step-by-step explanation:

Net of a prism is shown on the coordinate plane. We have to calculate the surface area of the prism.

To calculate the surface area of the net we will calculate the area of the four large rectangles and two squares given in the picture.

Total surface area of the net = 2× small squares + 4×large rectangles

= 2×(1×1) + 4×(1×2) = 2 + 8 = 10 square inch.

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marysya [2.9K]

Answer:

x = 115

Step-by-step explanation:

x = 115 because of alternate exterior angles

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