How more feet is the outer perimeter of the walkway than the perimeter of the pool is 48 ft
Since 6ft is the width of walkaway
Hence:
Let increase in width be 12
Let increase in length be 12
Now let determine How many
more feet is the outer perimeter of the walkway than the perimeter of the pool
Outer perimeter Number of feets = 2×(12+12)
Outer perimeter Number of feets = 2×24
Outer perimeter Number of feets = 48 ft
Inconclusion How more feet is the outer perimeter of the walkway than the perimeter of the pool is 48 ft
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brainly.com/question/11051185
first of all make a diagram write 20 and circle that and make a line write their 2× 10 and circle 2 and again make a line and write 2× 5 and make a circle and write 20= 2,2,5
Answer:
B
Step-by-step explanation:
the product is multiplication which is 2x3 and add 7
<span>4/10 8/20 2/5 These fractions you then simplify and get a product of 40 hope this helps you figure the answer out quicker.</span>
Answer:
14s^4-7s^2+15
Step-by-step explanation:
At the beginning the only bracket that is changing is the 3rd one because of the minus. (12s^4-6s^2+4s)+(6s^4-4s+27)-4s^4+s^2+12 then open the rest of the brackets. And start calculating.i will just to show you which ones u calculate together. (I'll separate the numbers depending on what they're squared to).
12s^4+6s^4-4s^4=14s^4
-6s^2-s^2=7s^2
27-12=15
All together is 14s^4-7s^2+15
