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Rus_ich [418]
3 years ago
14

Find the range of the data set 37 40 33 45 32 34

Mathematics
1 answer:
Lelechka [254]3 years ago
3 0

Answer: 13

Step-by-step explanation: The range of a group of numbers is the difference between the largest and smallest numbers. First, we can order these numbers from least to greatest.

32 - 33 - 34 - 37 - 40 - 45

Next, we can subtract the smallest number from our largest number.

<u>Smallest number = 32</u>

<u>Largest number = 45</u>

45 - 32 = 13

Therefore, the range of these numbers is 13.

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lara [203]

Answer:

Calculate the <u>first differences</u> between the y-values:

\sf 3 \underset{+1}{\longrightarrow} 4 \underset{+3}{\longrightarrow} 7 \underset{+5}{\longrightarrow} 12 \underset{+7}{\longrightarrow} 19

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\sf 1 \underset{+2}{\longrightarrow} 3 \underset{+2}{\longrightarrow} 5 \underset{+2}{\longrightarrow} 7

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--------------------------------------------------------------------------------------------------

<u>To determine the quadratic equation</u>

The coefficient of x^2  is always <u>half</u> of the <u>second difference</u>.

As the second difference is 2, and half of 2 is 1, the coefficient of x^2 is 1.

The standard form of a quadratic equation is:  y=ax^2+bx+c

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We have already determined that the coefficient of x^2 is 1.

Therefore, a = 1

From the given table, when x=0, y=12.

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Finally, to find b, substitute the found values of a and c into the equation, then substitute one of the ordered pairs from the given table:

\begin{aligned}\implies x^2+bx+12 & = y\\ \textsf{at }(1,19) \implies (1)^2+b(1)+12 & = 19\\ 1+b+12 & = 19\\b+13 & =19\\b&=6\end{aligned}

Therefore, the quadratic equation for the given ordered pairs is:

y=x^2+6x+12

7 0
2 years ago
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vichka [17]

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