Log (base 8) 2 +log (base 8) 4x^2 =1

1 answer:

6 0

Log (base8) 2 = 1/3

Log (base 8) (4x^2) + Log (base 8) 4 + 2Log (base 8) x = 2/3 + 2 Log (base 8) x

1/3 + 2/3 + 2 Log (base 8) x = 1

2 Log (base 8) x = 0

Log (base 8) x = 0

x = 8^0

x = 1.

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$y=\left \{ {{x^2 +2;\ \ x$

Step-by-step explanation:

In the graph we have a piecewise function composed of a parabola and a line.

The parabola has the vertex in the point (0, 2) and cuts the y-axis in y = 2.

The equation of this parabola is $y = x ^ 2 +2$

Then we have an equation line $y = -x + 2
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Note that the interval in which the parabola is defined is from -∞ to x = 1. Note that the parabola does not include the point x = 1 because it is marked with an empty circle " о ."

(this is $x< 1$ )

Then the equation of the line goes from x = 1 to ∞ . In this case, the line includes x = 1 because the point at the end of the line is represented by a full circle .

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