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Dennis_Churaev [7]
3 years ago
11

Woodley Stadium has nine gates with two ticket booths at each gate. If each ticket booth can process 600 fans per hour, what is

the stadium's maximum ingress throughput?
Mathematics
2 answers:
Vesna [10]3 years ago
7 0

Answer:

10,800

Step-by-step explanation:

9*2= 18

18*600=10,800

prisoha [69]3 years ago
4 0

Answer:

2,700

Step-by-step explanation:

2,700 fans would go in per hour you would have to divide the gates and 2 ticket booths and then with that you times 600 by the number you get by dividing

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So the mean is 72.97

We need to subtract the mean from each value and square it.
(65-72.97)^2= 63.5209
(68-72.97)^2=24.7009
(69-72.97)^2=15.7609
(70-72.97)^2=8.8209
(71-72.97)^2= 3.8809
(72-72.97)^2=0.9409
(90-72.97)^2=290.0209
(95-72.97)^2=485.3209

Now we add up the new values ( also consider their frequency) and find their mean.
Add the values
63.5209+(2 •24.7009=49.4018)+(5•15.7609=78.8045)+(8•8.8209=70.5672)+(7•3.8809=27.1663)+(3•0.9409=2.8227)+(2•290.0209=580.0418)+(2•485.3209=970.6418)= 1,842.967
Divide by total numburs to find the mean
1,842.967/ 30=61.43223333

The standar deviation is the square root of the mean so is
Square root of 61.43223333=7.837871735
Round to the nearest tenth
Standard Deviation is 7.8



7 0
3 years ago
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Answer:

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