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Dennis_Churaev [7]
3 years ago
11

Woodley Stadium has nine gates with two ticket booths at each gate. If each ticket booth can process 600 fans per hour, what is

the stadium's maximum ingress throughput?
Mathematics
2 answers:
Vesna [10]3 years ago
7 0

Answer:

10,800

Step-by-step explanation:

9*2= 18

18*600=10,800

prisoha [69]3 years ago
4 0

Answer:

2,700

Step-by-step explanation:

2,700 fans would go in per hour you would have to divide the gates and 2 ticket booths and then with that you times 600 by the number you get by dividing

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Enter the slope-intercept equation for the image of line ℓ after a clockwise rotation of 90°. (Hint: To find the image of line ℓ
Free_Kalibri [48]

Answer:

y = -2x - 2

Step-by-step explanation:

From the graph attached,

If the line 'l' passes through two points A(0, -1) and B(4, 1).

Rule for the rotation of any point (x, y), 90° clockwise about the origin is,

(x, y) → (y, -x)

By this rule,

A(0, -1) → A'(-1, 0)

B(4, 1) → B'(1, -4)

Let the equation of the line A'B' is,

y - y' = m(x - x')

where m = slope of the line A'B'

And (x', y') is a point lying on the line.

Slope of the line passing through A' and B' will be,

m = \frac{y_2-y_1}{x_2-x_1}

m = \frac{0+4}{-1-1}

m = -2

Therefore, equation of the line passing through (-1, 0) and slope = -2,

y - 0 = (-2)(x + 1)

y = -2x - 2

So the equation of the line after rotation of lie 'l' by 90° clockwise will be,

y = -2x - 2

7 0
3 years ago
A watercolor painting is 24 inches long by 11 inches wide. Ramon makes a border around the watercolor painting by making a mat t
sergeinik [125]

Given: It is given that the length of the painting is 24 inches and the width is  11 inches.

To find: Area of the mat

Solution:

The watercolor painting is 24 inches long by 11 inches wide.

So, the area of the painting is:

\text{Area of painting}=l\times b

\text{Area of painting}=24\times 11

\text{Area of painting}=264 \text{ in}^2

The length of painting with mat is = 24 in + 3 in + 3 in = 30 in

The width of painting with mat = 11 in + 3 in + 3 in = 17 in

\text{Area of painting with mat}=30\times 17

\text{Area of painting with mat}=510 \text{ in}^2

Now to calculate the area of mat subtracts the area of painting from the area of the mat.

\text{Area of mat}=\text{Area of painting with mat}-\text{Area of painting}\\

\text{Area of mat}=510-264

\text{Area of mat}=246 \text{ in}^2

Hence, the area of the mat is 246 in².

6 0
2 years ago
Your mum has saved $12,000 and has agreed to give you a share. Would you rather have 1/5 or 1/10 ?
zhenek [66]

Hello from MrBillDoesMath!

Answer:

1/5

Discussion:

$12000 * (1/5)   = $2400

$12000 * ( 1/10) = $1200


As 2400 > 1200, (1/5) is the best way to go

Thank you,

MrB

3 0
3 years ago
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Can some please help me?! I would appreciate it a lot!!!
TEA [102]

hello don't worry it's easy its A

5 0
3 years ago
2/3(6x−12)=8+□(2x−4)
rosijanka [135]

Answer:

-6

Step-by-step explanation:

one side of the equation is equaled to 4x-8 after you distribute the 2/3 so to make them equal you need a 2 on the other side 8-6 is 2

5 0
3 years ago
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