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oee [108]
2 years ago
9

Which ordered pair is NOT a solution of y= 2x -6?

Mathematics
2 answers:
spayn [35]2 years ago
7 0
It’s h because it’s not going to be negative
Andrej [43]2 years ago
3 0
I think the answer is h
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The sum of three numbers is 102. The first number is 6 more than the second. The third number is 4 times the second. What are th
const2013 [10]

Answer:

1st number: 22

2nd number: 16

3rd number: 64

Step-by-step explanation:

x + y + z = 102

x = 6 + y

z = 4y

plug that in!

(6 + y) + y + (4y) = 102

get rid of the parenthesis (I added them so you could see what I was replacing) and add like terms.

6 + 6y = 102

move 6 to the other side.

6y = 96

y = 16

now that you know one number, you can solve the equations for the rest!

x = 6 + (16)

z = 4(16)

__________________________________________________________

x = 22

y = 16

z = 64

6 0
2 years ago
Find the volume of the prism.<br> 3 ft<br> 7 ft<br> 5 ft
Taya2010 [7]

Answer:

105

Step-by-step explanation:

I am guess this prism is a rectangle

So 3 times 7 times 5 is 105

Thus the answer is 105

Hope this helps!

6 0
2 years ago
Read 2 more answers
55 is 40% of what number?
alexira [117]
40 over 100 and 55 over n cross multiply 55 x 100 and divide by 40.which gives you 137.5
4 0
3 years ago
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Using the Quadratic Formula, which of the following is the solution to the quadratic equation x2 - x - 20 = 0?
katovenus [111]
The answer to the question is c
4 0
3 years ago
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A train slows down as it rounds a sharp horizontal turn, going from 92.0 km/h to 54.0 km/h in the 16.0 s that it takes to round
Mnenie [13.5K]

Calculation of centripetal acceleration(ac):

a_c=\frac{v^2}{r}

we can change our speed in terms of m/s

v=54km/h=54*\frac{1000}{3600} m/s

now, we can plug these values

a_c=\frac{(54*\frac{1000}{3600})^2}{130}

a_c=1.73077m/s^2

Calculation of tangential acceleration(at):

a_t=\frac{\Delta v}{\Delta t}

now, we can plug values

a_t=\frac{(54-92)*\frac{1000}{3600} }{16}

now, we can simplify it

a_t=-0.65972 m/s^2

Calculation of resultant acceleration:

a=\sqrt{(a_c)^2+(a_t)^2}

now, we can plug values

a=\sqrt{(1.73077)^2+(-0.65972)^2}

a=1.85224m/s^2.............Answer

4 0
3 years ago
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