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3 years ago

4x-3y=30 3x+2y=22 (6,-2)

Mathematics

2 answers:

baherus [9]3 years ago

6 0

In place of x you keep 6 and in place of y you keep -2

IrinaVladis [17]3 years ago

5 0

(6,-2) is true for 4x-3y=30 but NOT for 3x+2y=22.

4*6=24

3*(-2)=-6

24-(-6) changes to 24+6 which equals 30

24+6=30.

3*6=18

2*(-2)=-4

18+(-4) would be changed to 18-4

18-4=14

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Which point do all exponential functions of the form y=a^x pass through

Bezzdna [24]

The answer should be A.

When we see the equation y=a^x we can relate to all the exponential functions, however, when the problem asked what points does all equations in that form pass through. I was instantly reminded by two facts.

One is that any number to the first is equal to itself. In other words, a^1=a

Another is that any number to the zero is equal to 1. a^x=1
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3 years ago

Please help I will give a medal

Tanya [424]

Funtion ! in vertex form is given by
f(x) = 4x^2 + 8x + 1 = 4(x^2 + 2x + 1/4) = 4(x^2 + 2x + 1 + 1/4 - 1) = 4(x + 1)^2 + 4(-3/4) = 4(x + 1)^2 - 3
Thus, the least minimun value is (-1, -3)
Also, the least minimum value of function 2 is (-1, 0)

Therefore, function 1 has the least minimum value at (-1, -3)

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3 years ago

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Pls help me ASAP plssss!!!

Nataly [62]

Answer:

7. $8

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Step-by-step explanation:

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3 years ago

Find the least common multiple (LCM) of 8y^6+ 144y^5+ 640y^4 and 2y^4 + 40y^3 + 200y^2.

Mice21 [21]

Answer:

LCM = $8y^{4}(y+ 10)^{2}(y + 8)$

Step-by-step explanation:

Making factors of $8y^{6}+ 144y^{5}+ 640y^{4}$

Taking $8y^{4}$ common:

$\Rightarrow 8y^{4} (y^{2}+ 18y+ 80)$

Using factorization method:

$\Rightarrow 8y^{4} (y^{2}+ 10y + 8y + 80)\\\Rightarrow 8y^{4} (y (y+ 10) + 8(y + 10))\\\Rightarrow 8y^{4} (y+ 10)(y + 8))\\\Rightarrow \underline{2y^{2}} \times 4y^{2} \underline{(y+ 10)}(y + 8)) ..... (1)$

Now, Making factors of $2y^{4} + 40y^{3} + 200y^{2}$

Taking $2y^{2}$ common:

$\Rightarrow 2y^{2} (y^{2}+ 20y+ 100)$

Using factorization method:

$\Rightarrow 2y^{2} (y^{2}+ 10y+ 10y+ 100)\\\Rightarrow 2y^{2} (y (y+ 10) + 10(y + 10))\\\Rightarrow \underline {2y^{2} (y+ 10)}(y + 10) ............ (2)$

The underlined parts show the Highest Common Factor(HCF).

i.e. HCF is $2y^{2} (y+ 10)$ .

We know the relation between LCM, HCF of the two numbers 'p' , 'q' and the numbers themselves as:

$HCF \times LCM = p \times q$

Using equations (1) and (2): $\Rightarrow 2y^{2} (y+ 10) \times LCM = 2y^{2} \times 4y^{2}(y+ 10)(y + 8) \times 2y^{2} (y+ 10)(y + 10)\\\Rightarrow LCM = 2y^{2} \times 4y^{2}(y+ 10)(y + 8) \times (y + 10)\\\Rightarrow LCM = 8y^{4}(y+ 10)^{2}(y + 8)$

Hence, LCM = $8y^{4}(y+ 10)^{2}(y + 8)$

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3 years ago

The quotient of 9 3/4 and 5/8

rewona [7]

Answer:

15.6

Step-by-step explanation:

The answer is 15.6 because if you divide 9 3/4 by 5/8, you get 78/5, or 15.6 in decimal form. Hope it helps!

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4 years ago

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