Answer: For the figure on the left {c}, the Area is 30m (squared) and the Perimeter is 46m.
For the figure on the right {d}, the Area is 32cm (squared) and the Perimeter is 34cm
Step-by-step explanation: (Please refers to the attached diagram)
We shall start with the diagram on the left. The first thing is to break it down into regular shapes, such as rectangles, squares, etc. The dotted line that runs from point C to point G divides the figure into two rectangles which are ABCG {or X} and GDEF {or Y}. Line AG measures 10m since it’s the same length as line BC. Similarly line GF measures 2m since it’s the same length as line DE. So rectangle “X” has dimensions;
L = 10, W = 1
Area of a rectangle = L x W
Area = 10 x 1
Area = 10m
Similarly rectangle Y has dimensions L= 10m and W = 2m
Hence area of rectangle “Y” is computed as
Area = L x W
Area = 10 x 2
Area = 20m
Area of the entire figure is derived as
Area of rectangle X + Area of rectangle Y, which is
10m + 20m = 30m {squared)
The perimeter of rectangle X is given as Perimeter = 2(L + W)
Perimeter = 2(10 + 1)
Perimeter = 2(11)
Perimeter = 22m
Also, perimeter of rectangle Y is derived as
Perimeter = 2(L + W)
Perimeter = 2(10+ 2)
Perimeter = 2(12)
Perimeter = 24m
Therefore the perimeter of the entire figure is derived as
Perimeter of rectangle X + perimeter of rectangle Y, which is
22m + 24m and that equals 46m
For the second figure on the right side of the page, we shall also break it down with the dotted lines that runs from point E to point G. That leaves us with rectangle ABGF {or P} and rectangle EGCD {or Q}.
Rectangle “P” has dimensions L= 4 and W = 2
Area of rectangle P = 4 x 2
Area of rectangle P = 8cm
Similarly area of rectangle Q is given as Area of Q = 8 x 3
Area of Q = 24cm
Area of the entire figure is derived as
Area of P + Area of Q,
8cm + 24cm
= 32cm {squared}
To compute the perimeter of rectangle P
Perimeter of a rectangle = 2(L + W)
Perimeter of rectangle P = 2(4 + 2)
Perimeter of rectangle P = 2(6)
Perimeter of rectangle P= 12cm
Similarly Perimeter of rectangle Q = 2(L + W)
Perimeter of rectangle Q = 2(8 + 3)
Perimeter of rectangle Q = 2(11)
Perimeter of rectangle Q = 22cm
Hence, perimeter of the entire figure is derived as perimeter of rectangle P + perimeter of rectangle Q which equals
12cm + 22cm and that equals
34cm.
Answer:
Step-by-step explanation:
As we can see in the figure that
The R, S, T ,and Q are the points on the circle O.
Also
The measurement of the circular arc is equivalent to the measurement of the angle at the center of the arc
So by this
m(major arc RQ) = m(∠QOR)
So,
And as we know that
All angles sum = 360°
Therefore
Part A)
Recall that:
1) The function represented by the graph of the function f(x) translated vertically n units up and horizontally m units left is:
2) The function represented by the graph of the function f(x) reflected over the x-axis is:
Now, notice that g(x) is the function f(x) reflected over the x-axis and then translated vertically 6 units up and horizontally 4 units left.
Answer Part A:
Options B, C, and D.
Part B) To graph g(x) we will reflect the graph of f(x) over the x-axis and then we will translate it vertically 6 units up and horizontally 4 units left.
We know that the graph of f(x)=|x| is:
The above graph reflected over the x-axis is:
Finally, the above graph translated vertically 6 units up and horizontally 4 units left is:
Answer part B:
