Hello!
To solve this question, we must first add the exponent into the number 7 before multiplying it by the number 6.
7 to the second power simply means 7x7.
7x7= 49
Now that the exponent is in the equation, we can multiply 49 by 6 to find your final answer.
6 x 49 = 294
I hope this helps answer your question! Have a great day!
-MMMski
Answer:
Sitting fee - 32$
Step-by-step explanation:
This is a system of equations(let x represent the sitting fee)
x+6y=50
x+11y=65
You want to isolate the x variable - x+6y-6y=50-6y ; x = 50-6y
Input this into the 2nd equation: 50-6y+11y=65 ; 50+5y=65
Subtract 50 from both sides. 5y=15 (Divided 5y on both sides) ; y=3
Now that y = 3 input this into any equation I choose the 1st one.
x+6(3) = 50 ; x + 18 = 50 (Subtract 18 on both sides to get x)
x = 32
Prove: 32 + 6(3) = 50 ; 32+18 = 50 ; 50 = 50 True
Perimeter of rectangle = length + length + width + width
To find the combinations, think of two numbers that each multiplied by 2 and added up to give 12 or 14
Rectangle with perimeter 12
Say we take length = 2 and width = 3
Multiply the length by 2 = 2 × 2 = 4
Multiply the width by 3 = 2 × 3 = 6
Then add the answers = 4 + 6 = 10
This doesn't give us perimeter of 12 so we can't have the combination of length = 2 and width = 3
Take length = 4 and width = 2
Perimeter = 4+4+2+2 = 12
This is the first combination we can have
Take length = 5 and width = 1
Perimeter = 5+5+1+1 = 12
This is the second combination we can have
The question doesn't specify whether or not we are limited to use only integers, but if it is, we can only have two combinations of length and width that give perimeter of 12
length = 4 and width = 2
length = 5 and width = 1
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Rectangle with perimeter of 14
Length = 4 and width = 3
Perimeter = 4+4+3+3 = 14
Length = 5 and width = 2
Perimeter = 5+5+2+2 = 14
Length = 6 and width = 1
Perimeter = 6+6+1+1 = 14
We can have 3 different combinations of length and width
I switched the x and y so it’s easier to see. The answer is (x-1)/(23).
