If you have at least as many equations as your have unknown variables, the 'system' is solvable (unless the equations are copies of eachother).
In this case, isolate one letter and plug it in the other. I'm going for the 2a in the bottom one (it doesn't matter)
2a - 4b = 12 => (divide by two and move the b's to the other side)
a = 6 + 2b. (plug this one into the top equation)
4(6+2b) + 6b = 10 => 24+8b+6b = 10 => 24 + 14b = 10 => 14b = -14 => b=-1
a = 6 + -2 = 4.
So a=4 and b=-1.
Answer:
it's blurry, you need a new picture
Answer:
y < 4x - 2
Step-by-step explanation:
D because some of the inputs have the same output therefor it is not a function
The correct answer is B.
Explanation
Since each interval mark is 1/4 of a unit, we will write this as 0.25. For the first point, 4 interval marks to the left of the y-axis makes it a negative number; 4(0.25) = 1; this makes the x-coordinate of this point -1. 2 interval marks above the x-axis makes it positive; 2(0.25) = 0.5; this makes the y-coordinate 0.5. This makes the first ordered pair (-1, 0.5).
The second point is on the y-axis. This makes the x-coordinate 0. It is 5 intervals above the x-axis; this makes it positive. 5(0.25) = 1.25 will be the y-coordinate, making the point (0, 1.25).
The third point is 3 intervals to the right of the y-axis; this makes it positive, and 3(0.25)=0.75 for the x-coordinate. It is 3 intervals below the x-axis; this makes it negative, and 3(0.25) = 0.75, making the y-coordinate -0.75. This puts the third point at (0.75, -0.75).
