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krok68 [10]
4 years ago
14

Need help on question 5 ASAP

Mathematics
1 answer:
erma4kov [3.2K]4 years ago
7 0
The answer is 1300 ft.

1 : 400 = 3 : 1200 = 3.25 : 1300

(The rate you were giving was 400 miles traveled per hour or 1:400. Then you had to figure out how far you would travel if you went for 3 hours and 15 minutes. 15 minutes of an hour can also be written as 1/4 of an hour or 0.25, so all you have to do is multiply both numbers by 3.25 in the ratio given and you will get you answer: 3.25 : 1300, simplified 1300 ft.)

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Triangle PQR has vertices at the following coordinates: P(0, 1), Q(3, 2), and R(5, -4). Determine whether or not triangle PQR is
vitfil [10]

Answer:

<h2>The triangle is not right triangle</h2>

Step-by-step explanation:

The steps in the above photo

I hope that is useful for you :)

7 0
3 years ago
Graph the following inequality 6x-2y&gt;8<br><br> Please help me and show me how to graph it.
Svetradugi [14.3K]

Answer:

6x - 2y > 8

<u><em>First, solve the inequality (Isolate the y-variable & put it in function format):</em></u>

<u><em /></u>6x - 2y > 8\\-2y > 8 - 6x\\(-1)(-2y) > (-1)(8-6x)\\2y < 6x-8\\y < \frac{6x-8}{2} \\y < 3x - 4

<u><em>Second, graph the function y = 3x - 4 on the graph.</em></u>

  • It should be linear.
  • Because the inequality is < and not ≤, the values on the line aren't included in the solution, so your line should be dotted, not solid.

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  • Since the inequality is <, that means the solutions are smaller than the solutions of the function 3x - 4.

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Can someone please help me with this
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Read 2 more answers
Which of the following is in the solution set of
cestrela7 [59]
The correct answer is D:

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Correct!
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4 years ago
HELP URGANT WILL GIVE 20 POINTS AND BRAINLIEST FOR FAST AND ACCURATE ANSWER !!!
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The sine of any acute angle is equal to the cosine of its complement. The cosine of any acute angle is equal to the sine of its complement. of any acute angle equals its cofunction of the angle's complement.

A

C

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Since m∠A = 22º is given, we know m∠B = 68º since there are 180º in the triangle. Since the measures of these acute angles of a right triangle add to 90º, we know these acute angles are complementary. ∠A is the complement of ∠B, and ∠B is the complement of ∠A.

If we write, m∠B = 90º - m∠A    (or m∠A = 90º - m∠B ), and we substitute into the original observation, we have:

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4 years ago
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