Answer:
The requirements that are necessary for a normal probability distribution to be a standard normal probability distribution are <em>µ</em> = 0 and <em>σ</em> = 1.
Step-by-step explanation:
A normal-distribution is an accurate symmetric-distribution of experimental data-values.
If we create a histogram on data-values that are normally distributed, the figure of columns form a symmetrical bell shape.
If X 
N (µ, σ²), then 
, is a standard normal variate with mean, E (Z) = 0 and Var (Z) = 1. That is, Z N (0, 1).
The distribution of these z-variates is known as the standard normal distribution.
Thus, the requirements that are necessary for a normal probability distribution to be a standard normal probability distribution are <em>µ</em> = 0 and <em>σ</em> = 1.
<span>Prime is the best option describes the number 5.The number 5 is a prime because prime can be divided evenly by 1, or itself. And it must be a whole number greater than 1.But 6 can be divided evenly by 1, 2, 3 and 6 so it is NOT a prime number (it is a composite number).</span>
Answer: 
.
Step-by-step explanation: The given decimal is 0.81818182, which is recurring and non-terminating decimal form.
Let us consider that
.
Thus, the fractional form of the decimal 0.81818182 is 9/11.
HCF
The higest common Factor of these two numbers can be found by breaking this down into it's prime factors.
404: 2*2*101
96: 2*2*2*2*2*3
HCF: 4
LCM
Using the same factors, the LCM can be found but taking the Highest number of prime factors from each set of numbers.
96:2 * 2 * 2 * 2 * 2 * <u><em>3</em></u>
404: 2 * 2 * 101
The Lowest Common Multiple is
2*2*2*2*2 * 3 * 101
LCM: 96 * 101 = 9696
HCF*LCM = 4 * 9696 = 38784
Multiple Original numbers together = 96 * 404 = 38784
In order to solve this,FIRST divide each price by the amount of their oz's. NEXT you find out which has the smallest numbers. FINALLY you have your answer.
4.29 divided by 12 is 0.3575
2.89 divided by 8 is 0.36125
5.59 divided by 6 is 0.43
5.29 divided by 14 is 0.37
YOUR ANSWER IS A :D
