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sergeinik [125]
3 years ago
13

How many ounces are 3 pounds ?

Mathematics
2 answers:
Natalka [10]3 years ago
4 0

Answer: 48 ounces in 3 pounds (16 ounces to a pound)

guajiro [1.7K]3 years ago
3 0

Answer:

if you multiply the mass value by 16 you would get  48

3 times 16 equals 48

Step-by-step explanation:

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Choice 1, 3, and 4 are topologically equivalent. These figures each have two holes. 

Choice 2 has three holes and is different from the other. 

Topologically equivalent figures are figures that can be rearranged to form another shape without breaking.</span>
8 0
3 years ago
Help ASAP!
Tema [17]

Answer:

B

Step-by-step explanation:

\boxed{area \: of \: sector =  \frac{1}{2} {r}^{2} θ }

Radius= diameter ÷2

r= 32 ÷2

r= 16

\frac{1}{2}  {r}^{2} θ =  \frac{512\pi}{3}

Substitute r= 16,

\frac{1}{2} ( {16}^{2} )(θ) =  \frac{512\pi}{3}

128 \: θ =  \frac{512\pi}{3}  \\ θ =  \frac{512\pi}{3}  \div 128 \\ θ =  \frac{512\pi}{384}

Divide the denominator and numerator by 128:

θ =  \frac{4\pi}{3}

Thus, the answer is B.

3 0
3 years ago
How does deposition help explain the layers that are often found in sedimentary rock?
julia-pushkina [17]
Because it is deposition
6 0
3 years ago
Saeed wants to have his birthday at an amusement park with a few of his friends but he can't spend no more then $80. The amuseme
OLEGan [10]

Answer:

T=35X6.50

Step-by-step explanation:

4 0
3 years ago
(Hehe...Please ignore the markings)
inysia [295]

Answer:

See below:

Step-by-step explanation:

Problem 1:

Multiply Equation 1 by 4, keep Equation 2 the same.

x+y=8, multiply each term by 4:

4*x=4x, 4*y=4y, 8*4=32

so, the equivalent system is: 4x+4y=32 and x-y=2

Solve the system of equations:

x-y=2 becomes x=y+2

plug into 4x+4y=32 to solve for y

4(y+2)+4y=32---> 4y+8+4y=32--->8y=24---> y=3

Plug into x-y=2---> x-3=2---> x=5

Problem 1 Answer:

Equivalent system: 4x+4y=32, x-y=2; solution: x=5, y=3

Problem 2:

Keep Equation 1 the same. Add 1 and 2.

To add an equation, add the left sides together, and then the rights.

so: x+y=8 + x-y=2 gives us: 2x=10

solve for x ---> 2x/2=10/2--->x=5

plug x into x+y=8--->5+y=8--->y=3

Problem 2 answer:

Equivalent system: x+y=8, 2x=10; solution:x=5, y=3

Problem 3:

Subtract Equation 2 from 1, and keep 2 the same.

To subtract an equation, subtract the left sides, then the rights. We are subtracting 1<em> from </em>2, so its 2-1.

x-y=2 - x+y=8 gives us: -2y=-6

Solve for y by dividing by -2-->-2y/-2=-6/-2---> y=3

Plug into x-y=2---> x-3=2---> x=5

Problem 3 answer:

Equivalent system: -2y=-6, x-y=2; solution: x=5, y=3

Problem 4:

Multiply the sum of Equation 1 and 2 by a factor of 3. Keep equation 2 the same.

First we add 1 and 2: (we did this earlier) ---> 2x=10 ---> now we multiply it all by 3---> 2x*(3)=10*(3)---> this gives us: 6x=30---> now divide by 6 to solve for x: 6x/6=30/6 gives us: x=5

Now, solve for y by plugging x into equation 2: x-y=2---> 5-y=2--->y=3

Problem 4 answer:

Equivalent system: 6x=30, x-y=2; solution: x=5, y=3

______

Quick Tip: One thing inherent of Equivalent systems is that they have the same set of solutions. Thus, we know the systems are equivalent when they have the same set of solutions for x and y. Moreover, you don't need to solve every time after you attempt to find an equivalent system, instead, just plug in the values found in problem 1 to each new set of equations to test if they are equivalent.

If we find x=5 and y=3 for x+y=8 and x-y=2, then all we have to do is plug them in to 6x=30 and -2y=-6 to see if they are equivalent.

6(5)=30 ---> true

-2(3)=-6 ---> true

3 0
3 years ago
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