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sergeinik [125]
2 years ago
13

How many ounces are 3 pounds ?

Mathematics
2 answers:
Natalka [10]2 years ago
4 0

Answer: 48 ounces in 3 pounds (16 ounces to a pound)

guajiro [1.7K]2 years ago
3 0

Answer:

if you multiply the mass value by 16 you would get  48

3 times 16 equals 48

Step-by-step explanation:

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Y=3x−4<br> y=−12x+3<br> solution <br> solve by graphing
Anna11 [10]

Answer:

(7/15,−13/5)

Equation Form:

x=7/15,y=−13/5

Step-by-step explanation:

Solve for the first variable in one of the equations, then substitute the result into the other equation.

7 0
2 years ago
Simplify the product using FOIL. (3x + 4)(2x – 6)
Arturiano [62]

Answer:

6x^2 - 10x - 24

Step-by-step explanation:

  1. Do 3x times 2x which is 6x^2
  2. Do 3x times - 6 which is -18x
  3. Do 4 times 2x which is 8x
  4. Do 4 times - 6 which is - 24
  5. You get 6x^2 - 18x + 8x - 24
  6. Simplyify to get the answer
5 0
3 years ago
Read 2 more answers
What is the square root of <br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B163%7D%20" id="TexFormula1" title=" \sqrt{163} " a
crimeas [40]

Hi,

\sqrt{163} = 12.76

There are no other simple steps to reduce the square root of one hundred and sixty-three.

The actual square root value is ≈12.767145334803704

But we have taken only significant figures and it is as 12.76.


Hope it helps! :)

5 0
3 years ago
PLEASE HURRY
horsena [70]

Answer:6,2

Step-by-step explanation:you need to add each step and divide

8 0
3 years ago
Read 2 more answers
Suppose a basketball player has made 231 out of 361 free throws. If the player makes the next 2 free throws, I will pay you $31.
statuscvo [17]

Answer:

The expected value of the proposition is of -0.29.

Step-by-step explanation:

For each free throw, there are only two possible outcomes. Either the player will make it, or he will miss it. The probability of a player making a free throw is independent of any other free throw, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Suppose a basketball player has made 231 out of 361 free throws.

This means that p = \frac{231}{361} = 0.6399

Probability of the player making the next 2 free throws:

This is P(X = 2) when n = 2. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{2,2}.(0.6399)^{2}.(0.3601)^{0} = 0.4095

Find the expected value of the proposition:

0.4095 probability of you paying $31(losing $31), which is when the player makes the next 2 free throws.

1 - 0.4059 = 0.5905 probability of you being paid $21(earning $21), which is when the player does not make the next 2 free throws. So

E = -31*0.4095 + 21*0.5905 = -0.29

The expected value of the proposition is of -0.29.

3 0
2 years ago
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