Answer:
18° and 72°
Step-by-step explanation:
Complimentary angles form 90°
We have an angle (x) 4 times larger than the other (y).
Well actually, a system of equations isn't required, so forget about x and y, just divide 90 by 5. This gives you 18, one of the angle's measurements is 18°. Multiply 18 by 4 and get 72. The other angle's measurement is 72°.
Answer:
The evaluation of the equation 3 .912+s=5.313 yields; s = 1.401
Evaluation of one variable equation
According to the questions;
We are required to evaluate the equation; 3 .912+s=5.313
Hence, we must subtract 3.912 from both sides of the equation as follows;3 .912+s -3.912 = 5.313 - 3.912.s = 1.401
Step-by-step explanation:
mark me brainliest!!
Answer: its 37
Step-by-step explanation:
its 37
Using the <u>normal approximation to the binomial</u>, it is found that there is a 0.994 = 99.4% probability that we will have enough seats for everyone who shows up.
In a normal distribution with mean
and standard deviation
, the z-score of a measure X is given by:
- It measures how many standard deviations the measure is from the mean.
- After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
- The binomial distribution is the probability of <u>x successes on n trials</u>, with <u>p probability</u> of a success on each trial. It can be approximated to the normal distribution with
.
In this problem:
- 15% do not show up, so 100 - 15 = 85% show up, which means that
. - 300 tickets are sold, hence
.
The mean and the standard deviation are given by:


The probability that we will have enough seats for everyone who shows up is the probability of at most <u>270 people showing up</u>, which, using continuity correction, is
, which is the <u>p-value of Z when X = 270.5</u>.



has a p-value of 0.994.
0.994 = 99.4% probability that we will have enough seats for everyone who shows up.
A similar problem is given at brainly.com/question/24261244
Answer:
-4.
Step-by-step explanation:
-4x - 15 = -4x + 6
has no solution.