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allsm [11]
4 years ago
9

Whats the product (-2x-9y^2)(-4x-3)

Mathematics
1 answer:
Inessa05 [86]4 years ago
8 0
Hello there!

(-4x-3)(-2x-9y^{2})
-4x(-2x-9y^{2}) = 8x^{2} +36xy^{2}
-3(-2x-9y^{2}) = 6x + 27y^{2}

36xy^2 + 8x^2 + 27y^2 + 6x is your product polynomial.

I hope this helps!
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PLEASE HELP ME! <br><br> EXPLANATION = BRAINLIEST<br><br> the area is ___ square units
Usimov [2.4K]

Answer:

50 units²

Step-by-step explanation:

Solve for both long sides:

6² + 8² = x²

36 + 64 = x²

100 = x²

x = 10

Solve for both short sides:

3² + 4² = x²

9 + 16 = x²

25 = x²

x = 5

Area:

5 x 10 = 50

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6 0
3 years ago
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Lines l and k are parallel to each other. A=120 degrees. and C=80 degrees. What is the number of degrees in B??
Aleonysh [2.5K]

Answer:

B = 160°

Step-by-step explanation:

This is how I solved it (I hope the explanation isn't too confusing):

Since L and K are parallel, I drew a straight line from A to B. By doing this, I'm making a triangle: ΔABC

Then I solved for the angles of the triangle. First, we are given that ∠C = 80° and ∠A = 120°. Although, when I drew the vertical line from A to B, it made a 90° (see attachment).

So what we basically did was break ∠A into two parts: an angle inside ΔABC and one outside. To find the interior angle, simply subtract 90° from 120° to get 30°.

There are 180° in a triangle, so add the two interior angles you know:

30° + 80° = 110°

Then subtract 110° from 180° to find the final interior angle which is:

180° - 110° = 70°.

To find the measure of angle B, you must add all of the parts together, so the 90° outside angle and the 70° interior angle:

90° + 70° = 160°

5 0
3 years ago
Find the solution to the system of equations: x 3y = 7 and 2x 4y = 8 1. isolate x in the first equation: 2. substitute the value
DIA [1.3K]

The solution to the system of equation are x = -2 and y = 3

<h3>How to find the solution of a system of equation?</h3>

x + 3y = 7

2x + 4y = 8

Let's isolate x in the first equation

x = 7 - 3y

substitute the value of x in the second equation.

Therefore,

2(7 - 3y) + 4y = 8

14 - 6y + 4y = 8

-2y = 8 - 14

-2y = -6

y = -6 / -2

y = 3

Hence,

x + 3(3) = 7

x = 7 - 9

x = -2

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4 0
2 years ago
Given the following sets: A = {1,2,3,4,5,6,7}, B = {2,4,7,9, 10}, C={1,3,5,7,9}, U = {1,2,3,4,5,6,7,8,9,10,11,12}
Blababa [14]

Answer:

thats not a real question what do you mean...

Step-by-step explanation:

3 0
3 years ago
I really need help guys can some one plz help me it's for 10 points
11111nata11111 [884]

Answer:

\sqrt{8}----- 2units,2units

\sqrt{7} ------\sqrt{5}units,\sqrt{2}units

\sqrt{5}-------1unit,2units

3------2units, \sqrt{5}units

Step-by-step explanation:

Use pythagorean's theorem to solve each pair individually.

The instructions say that you have the two sides (a and b) and you have to match it with their hypothenuse.

Formula: c^2=a^2+b^2

1. a=\sqrt{5}, b=\sqrt{2}

Plug this into the formula.

c=\sqrt{(\sqrt{5} )^2+(\sqrt{2})^2 }

The square here eliminates the roots.

c=\sqrt{5+2}\\ c=\sqrt{7}

2. a=\sqrt{3}, b=4

c=\sqrt{(\sqrt{3} )^2+(4)^2}\\ c=\sqrt{3+16}\\ c=\sqrt{19}

3. a=2, b=\sqrt{5}

c=\sqrt{(2)^2+(\sqrt{5})^2 }\\ c=\sqrt{4+5}\\ c=\sqrt{9}\\ c=3

4. a=2, b=2

c=\sqrt{(2)^2+(2)^2}\\ c=\sqrt{4+4}\\ c=\sqrt{8}

5. a=1, b=2

c=\sqrt{(1)^2+(2)^2}\\ c=\sqrt{1+4}\\ c=\sqrt{5}

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