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2 years ago

Lines l and k are parallel to each other. A=120 degrees. and C=80 degrees. What is the number of degrees in B??

Mathematics

1 answer:

Aleonysh [2.5K]2 years ago

5 0

Answer:

B = 160°

Step-by-step explanation:

This is how I solved it (I hope the explanation isn't too confusing):

Since L and K are parallel, I drew a straight line from A to B. By doing this, I'm making a triangle: ΔABC

Then I solved for the angles of the triangle. First, we are given that ∠C = 80° and ∠A = 120°. Although, when I drew the vertical line from A to B, it made a 90° (see attachment).

So what we basically did was break ∠A into two parts: an angle inside ΔABC and one outside. To find the interior angle, simply subtract 90° from 120° to get 30°.

There are 180° in a triangle, so add the two interior angles you know:

30° + 80° = 110°

Then subtract 110° from 180° to find the final interior angle which is:

180° - 110° = 70°.

To find the measure of angle B, you must add all of the parts together, so the 90° outside angle and the 70° interior angle:

90° + 70° = 160°

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3 years ago

Calculating the degrees of freedom, the sample variance, and the estimated standard error for evaluations using the t statistic

Yuliya22 [10]

Answer:

a) For the first part we have a sample of n =10 and we want to find the degrees of freedom, and we can use the following formula:

$df = n-1= 10-1=9$

d.9

b) $s^2 = \frac{SS}{n-1}= \frac{600}{41-1}= 15$

a.15

c) For this case we have the sample size n = 25 and the sample variance is $s^2 =400$ , the standard error can founded with this formula:

$SE = \frac{s^2}{\sqrt{n}}= \frac{400}{\sqrt{25}}= 80$

Step-by-step explanation:

Part a

For the first part we have a sample of n =10 and we want to find the degrees of freedom, and we can use the following formula:

$df = n-1= 10-1=9$

d.9

Part b

From a sample we know that n=41 and SS= 600, where SS represent the sum of quares given by:

$SS = \sum_{i=1}^n (X_i -\bar X)^2$

And the sample variance for this case can be calculated from this formula:

$s^2 = \frac{SS}{n-1}= \frac{600}{41-1}= 15$

a.15

Part c

For this case we have the sample size n = 25 and the sample variance is $s^2 =400$ , the standard error can founded with this formula:

$SE = \frac{s^2}{\sqrt{n}}= \frac{400}{\sqrt{25}}= 80$

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