Answer:
B
Step-by-step explanation:
Answer:
see below
Step-by-step explanation:
The circumference is given by
C = pi *d
C = 15.5 pi
If we approximate pi by 3.14
C = 15.5 * 3.14
C =48.67
If we use the pi button
C =48.69486813
<span>0.3046% chance of damaging at least one of five payloads.
First, determine how many standard deviations it takes for the parachute to open at 100 meters. So
200 m - 100 m = 100 m
100 m / 31 m = 3.2258
Looking up on a standard normal table, the probability of having that deviation or higher is 0.00061, or 0.061%
Since you're looking for the probability of damaging at least one of five, the easiest way of calculating that is to subtract from 1 the probability of having all five parachutes successfully deploy. So
1 - (1 - 0.00061)^5 = 1 - 0.99939^5 = 1 - 0.996953719 = 0.003046281 = 0.3046%</span>
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