I'm assuming a 5-card hand being dealt from a standard 52-card deck, and that there are no wild cards.
A full house is made up of a 3-of-a-kind and a 2-pair, both of different values since a 5-of-a-kind is impossible without wild cards.
Suppose we fix both card values, say aces and 2s. We get a full house if we are dealt 2 aces and 3 2s, or 3 aces and 2 2s.
The number of ways of drawing 2 aces and 3 2s is
and the number of ways of drawing 3 aces and 2 2s is the same,
so that for any two card values involved, there are 2*24 = 48 ways of getting a full house.
Now, count how many ways there are of doing this for any two choices of card value. Of 13 possible values, we are picking 2, so the total number of ways of getting a full house for any 2 values is
The total number of hands that can be drawn is
Then the probability of getting a full house is
Y>3 is the correct answer because more than 3 inches of rain fell.
They want to know the probability of landing in the blue and red section at the same time. In other words, they want to know the probability of landing in the purple section.
We'll need the area of the purple square. This square is 1.5 inches by 1.5 inches. This is because 4 - 2.5 = 1.5
So the purple square has an area of 1.5*1.5 = 2.25 square inches
Divide this over the total area of the largest square (which is 9x9) to get 2.25/81 = 0.02777... where the 7's go on forever
Round that to two decimal places. The final answer is 0.03
Side note: 2.25/81 is equivalent to the reduced fraction 1/36 (express 2.25/81 as 225/8100 and then divide both parts by the GCF 225)
Answer:
9 1/6
You may use a fraction calulator for this question by the way!
Hope this helps!
Sorry if its wrong!
Have a nice day!
The average number of goals per game Peter scores, rounded to one decimal place is 1.6
<u><em>Explanation</em></u>
In first two games Peter scored 2 goals each. So, total score in two games = (2×2)= 4
In one game he scored 0 goal and in next two games he scored 3 goals each, so the total is (3×2)= 6
In the last four games he scored 1 goal in each, so the total is (1×4)= 4
So, the total score in all 
games 
Thus, the average number of goals 
So, the average number of goals per game Peter scores, rounded to one decimal place is 1.6
