The air force plane travelled for a total of 6.9 hours.
<u>SOLUTION:
</u>
Given, An Air Force plane left Nairobi and flew west at an average speed of 159 mph. A cargo plane left sometime later flying in the same direction at an average speed of 207 mph. After flying for 5.3 hours the cargo plane caught up with the Air Force plane.
We have to find the number of hours the Air Force plane flew before the cargo plane caught up.
Now, we know that, 
For air force plane 
Now, when cargo plane caught the air force plane the distance travelled by the planes will be equal.
So, 
Time taken by air force plane = 6.9 hrs
Answer:
21
Step-by-step explanation:
Answer:
x = 
Step-by-step explanation:
7.4x + 4.1(2x − 4) = −2.3(x − 6) − 21.6
Multiply both sides by 10:
7.4x×10+4.1(2x-4)×10=-2.3(x-6)×10-21.6×10
Refine:
74x+41(2x-4)=-23(x-6)-216
Distributive Property:
74x+82x-164=-23(x-6)-216
Combine like terms:
156x-164=-23(x-6)-216
Distributive Property:
156x-164=-23x+138-216
Combine like terms:
156x-164=-23x-78
Add 164 to both sides:
156x-164+164=-23x-78+164
Simplify:
156x=-23x+86
Add 23x to both sides:
156x+23x=-23x+86+23x
Simplify:
179x=86
Divide both sides by 179:
=
Simplify:
x =
B is called "the vertical intercept" and is the value of y when x = 0. Something like an initial value!
64 degrees because it’s not the 101 and it’s too short to be the 51 so it Hass to be the 64° one
