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AVprozaik [17]
4 years ago
10

I will mark branlest if you are right

Mathematics
1 answer:
schepotkina [342]4 years ago
6 0

Answer:

1) y=(-1/4)x+(11/4)

2) y=(4)x-33

3) y=(2/3)x-11/3

4) y=(5)x-2

5) y=(3)x-7

6) y=(-1/4)x+(6)

Step-by-step explanation:

1) y=mx+b  3=(-1/4)(-1)+b  b= 11/4

2) y=mx+b  -5=(4)(7)+b  b= -33

3) y=mx+b  -5=(2/3)(-2)+b  b= -11/3

4) y=mx+b  3=(5)(1)+b  b= -2

5) y=mx+b  -1=(-3)(-2)+b  b= -7

6) y=mx+b  7=(1/4)(4)+b  b= 6

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4 0
3 years ago
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PLEASE ANSWER I NEED HELP
lukranit [14]
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4 0
3 years ago
Can someone plz help me solve this problem I need help plz someone help me!
cestrela7 [59]

Answer:   25 < P < 36

              15/4 < w < 26/4

              35/4 < L < 46/4

<u>Step-by-step explanation:</u>

Perimeter is BETWEEN 25 and 36

           25 <    P    < 36

Graph:  O--------------O

            25              36

Perimeter = 2L + 2w  ; substitute L = w + 5        

             25 < 2(w + 5) + 2w < 36

             25 < 2w + 10  + 2w < 36

              25 <  4w + 10          < 36

               15 <           4w         < 26

               \dfrac{15}{4} <             w         < \dfrac{26}{4}

              3\dfrac{3}{4}  <              w        <  6\dfrac{1}{2}

Graph:     O------------------------O

              3\dfrac{3}{4}                             6\dfrac{1}{2}

Perimeter = 2L + 2w  ; L = w + 5   --> w = L - 5      

             25 < 2L + 2(L - 5)  < 36

             25 < 2L + 2L  - 10 < 36

              25 <  4L - 10        < 36

              35 <           4L      < 46

              \dfrac{35}{4} <             L       < \dfrac{46}{4}

              8\dfrac{3}{4}  <            L      <  11\dfrac{1}{2}

Graph:     O------------------------O

               8\dfrac{3}{4}                          11\dfrac{1}{2}

Note: Make sure you use OPEN dots when graphing.

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