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White raven [17]
3 years ago
7

What are the solutions to the quadratic equation -2x^2 + 6x + 3 = 0?

Mathematics
1 answer:
mario62 [17]3 years ago
5 0

For this, we will be using the quadratic formula, which is x=\frac{-b+/-\sqrt{b^2-4ac}}{2a}, with a=x^2 coefficient, b=x coefficient, and c = constant. Our equation will look like this: x=\frac{-6+/-\sqrt{6^2-4*(-2)*3}}{2*(-2)}


Firstly, solve the multiplications and the exponents: x=\frac{-6+/-\sqrt{36+24}}{-4}


Next, do the addition: x=\frac{-6+/-\sqrt{60}}{-4}


Next, your equation will be split into two: x=\frac{-6+\sqrt{60}}{-4},\frac{-6-\sqrt{60}}{-4} . Solve them separately, and your answer will be x=-0.436,3.436

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