Answer:
A, C, D
Step-by-step explanation:
One way to answer this question is to use synthetic division to find the remainder from division of the polynomial by (x-3). If the polynomial is written in Horner form, evaluating the polynomial for x=3 is substantially similar.
A(x) = ((x -2)x -4)x +3
A(3) = ((3 -2)3 -4)3 +3 = -3 +3 = 0 . . . . . has a factor of (x -3)
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B(x) = ((x +3)x -2)x -6
B(3) = ((3 +3)3 -2)3 -6 = (16)3 -6 = 42 . . . (x -3) is not a factor
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C(x) = (x -2)x^3 -27
C(3) = (3 -2)3^3 -27 = 0 . . . . . . . . . . . . . has a factor of (x -3)
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D(x) = (x^3 -20)x -21
D(3) = (3^3 -20)3 -21 = (7)3 -21 = 0 . . . . has a factor of (x -3)
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The polynomials of choice are A(x), C(x), and D(x).
Answer:-1/32
Step-by-step explanation:
First term=a=1024
Common ratio=r=-512/1024
r=-1/2
Using them formula
Tn=a x r^(n-1)
T16=1024 x (-1/2)^(16-1)
T16=1024 x (-1/2)^15
T16=1024 x -1/32768
T16=-1024/32768
T16=-1/32
Answer:
it is not possible result is not given so it is not possible
9(2x-1)=3(x+2)+3x
18x-9=3x+6+3x
18x-9=6x+6
18x-6x=6+9
12x=15
x=15/12
x=5/4
4.065323 × 10^13
Hope this helps!
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