2/5 in decimal form is 0.4.
Hope this helps!
Question:
A drink dispenser in a fast-food restaurant holds 250 litres of lemonade. How many 0.6-litre drinks can be dispensed before a refill is needed?
Answer:
The number 0.6-litre drinks can be dispensed before a refill is needed is 416
Step-by-step explanation:
Given:
The capacity of the drink dispenser = 250 litres
To Find:
Number of 0.6-litre drinks can be dispensed before a refill is needed = ?
Solution
Let the number of 0.6-litre drinks can be dispensed before a refill is needed be x
Then

On substituting the values we get
x = 416. 667
Thus only 416 can be filled
Answer: room 101 and room 107
Step-by-step explanation:
In room 101, the ratio of boys to girls is 16:12. This is further simplified to its lowest fraction by dividing by 4. It becomes 4:3
In room 104, the ratio of boys to girls is 20:9. This cannot be further simplified to its lowest fraction.
In room 107, the ratio of boys to girls is 12:9. This is further simplified to its lowest fraction by dividing by 3. It becomes 4:3
Therefore, room 101 and room 107 have the same ratio.
So if the main question is 9q x 3 it would equal 27q
Answer:
The value of given expression i.e Ф is 90° and - 30°
Step-by-step explanation:
Given as :
4 cos²Ф + 2 sinФ = 2
∵ sin²Ф + cos²Ф = 1 , so , cos²Ф = 1 - sin²Ф
Or, 4 ( 1 - sin²Ф ) + 2 sinФ = 2
Or, 4 - 4 sin²Ф + 2 sinФ = 2
or, 4 sin²Ф - 2 sinФ - 4 + 2 = 0
or, 4 sin²Ф - 2 sinФ - 2 = 0
or, 2 sin²Ф - sinФ - 1 = 0
or, 2 sin²Ф - 2 sinФ + sinФ - 1 = 0
Or, 2 sinФ ( sinФ - 1 ) + 1 ( sinФ - 1 ) = 0
∴ ( sinФ - 1 ) ( 2 sinФ + 1 ) = 0
i.e ( sinФ - 1 ) = 0 And ( 2 sinФ + 1 ) = 0
since ( sinФ - 1 ) = 0
So, sinФ = 1
Or, Ф =
= 90°
And ( 2 sinФ + 1 ) = 0
Or, 2 sinФ = - 1
Or, sinФ = - 
Or, Ф =
= - 30°
Hence the value of given expression i.e Ф is 90° and - 30° Answer