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julsineya [31]
3 years ago
7

What is simplify x-2y=-2​

Mathematics
1 answer:
svp [43]3 years ago
3 0
X=-2+2y
x=2(-1+y)
x=2(y-1)
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Please help me with the question below including the graph.
ehidna [41]

Answer:

13.50 ≤ 1.20x + 3

Step-by-step explanation:

Janie is saving for a CD, which costs $13.50. Janie can earn more than that amount, but needs to save at least that much to buy the CD. So, the amount of money she has needs to be greater than or equal to $13.50.

Next, Janie has $3 to begin with. Although she already has some money to start with, that is still not enough to purchase her CD. To earn money, she will do chores ($1.20 per chore). We do not know the amount of chores she will do, so we can mark that as variable x.

If we put that all together, we will get 13.50 ≤ 1.20x + 3. If you solver this equation, you can solve how many chores she will have to do, but that is not part of the question!!

Now, for the graph. A closed dot represents if it is not only greater or less than, but it also has a possibility to be equal as well. So, this dot will be closed. As I said before, the amount of money she has all together has to be greater than or equal to $13.50. Starting from the dot, you will draw the arrow to the right, which symbolizes that all of these numbers are the solution.

I hope this helped you! Have a great rest of your day.

6 0
3 years ago
HELP PLS APASAPA I WILL GIVE BRAIN
Alex777 [14]

Answer:

you answer will be a binary number

7 0
2 years ago
Plz help :(
Effectus [21]

Answer:

Step-by-step explanation:

6 0
3 years ago
Select the correct answer.
iris [78.8K]

The future value of $1,000 invested at 8% compounded semiannually for five years is \bold{\$ 1,480}

<u>Solution:</u>

\bold{A = P (1 + i )^{n}} ----------- equation 1

A = future value  

P= principal amount  

i = interest rate

n = number of times money is compounded  

P = 1000

i = 8 %

\mathrm{n} = \text { compounding period } \times \text {number of years}

(Compounding period for semi annually = 2)

\mathrm{n} = \text { compounding period } \times \text {number of years}

Dividing “i” by compounding period

i = \frac{8 \%}{2} = 0.04

Solving for future value using equation 1

\begin{array}{l}{A = 1000(1 + 0.04)^{10}} \\\\ {=1000 (1.04)^{10}}\end{array}

= 1480.2

\approx 1,480 \$

3 0
3 years ago
Help me please with 2 and 3
IRINA_888 [86]
The answer for #2 is A

And the answer for #3 is B

6 0
3 years ago
Read 2 more answers
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