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vitfil [10]
3 years ago
10

A grocer wants to make a 10-pound mixture of peanuts and cashews that he can sell for $4.75 per pound. If peanuts cost $4.00 per

pound and cashews cost $6.50 per pound, how many pounds of each should he use? Let p = pounds of peanuts and let c = pounds of cashews. Write a system of equations that could be used to solve the problem.
will mark as brainliest
Mathematics
1 answer:
andrew11 [14]3 years ago
7 0

Answer:

ANSWER 1: He should use 3 pounds of cashews.

ANSWER 2: He should use 7 pounds of peanuts.

Step-by-step explanation:

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-4/9 + (-1/3) ? Helppppp
Alex

Answer:

- 7/9

Step-by-step explanation:

-4/9 + (-1/3)

= -(4/9) - (1/3)

= - (4/9 + 1/3)

= - (4/9 + 3/9)

= - [(4 + 3) / 9 ]

= - 7/9

5 0
3 years ago
Please help
aleksklad [387]

Answer:

B

Step-by-step explanation:

The value of the 4 in 14.8 is 10 times the value of the 4 in 3.46.

6 0
2 years ago
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78 students are going to be divided into 24 groups and the number of each group member will be either 4 or 2. How many groups of
True [87]
36 and 45 that will be your answer
7 0
3 years ago
33. Suppose you were on a planet where the
tatyana61 [14]

<u>Answer:</u>

a) 3.675 m  

b) 3.67m

<u>Explanation:</u>

We are given acceleration due to gravity on earth =9.8ms^-2

And on planet given = 2.0ms^-2

A) <u>Since the maximum</u><u> jump height</u><u> is given by the formula  </u>

\mathrm{H}=\frac{\left(\mathrm{v} 0^{2} \times \sin 2 \emptyset\right)}{2 \mathrm{g}}

Where H = max jump height,  

v0 = velocity of jump,  

Ø = angle of jump and  

g = acceleration due to gravity

Considering velocity and angle in both cases  

\frac{\mathrm{H} 1}{\mathrm{H} 2}=\frac{\mathrm{g} 2}{\mathrm{g} 1}

Where H1 = jump height on given planet,

H2 = jump height on earth = 0.75m (given)  

g1 = 2.0ms^-2 and  

g2 = 9.8ms^-2

Substituting these values we get H1 = 3.675m which is the required answer

B)<u> Formula to </u><u>find height</u><u> of ball thrown is given by  </u>

 \mathrm{h}=(\mathrm{v} 0 * \mathrm{t})+\frac{\mathrm{a} *\left(t^{2}\right)}{2}

which is due to projectile motion of ball  

Now h = max height,

v0 = initial velocity = 0,

t = time of motion,  

a = acceleration = g = acceleration due to gravity

Considering t = same on both places we can write  

\frac{\mathrm{H} 1}{\mathrm{H} 2}=\frac{\mathrm{g} 1}{\mathrm{g} 2}

where h1 and h2 are max heights ball reaches on planet and earth respectively and g1 and g2 are respective accelerations

substituting h2 = 18m, g1 = 2.0ms^-2  and g2 = 9.8ms^-2

We get h1 = 3.67m which is the required height

6 0
3 years ago
Chloe and tino have a combined age of 48. three years ago chloe was double the age tino is now. find tinos age
jeka94

As  given Chole and Tinos age , the present age of Tino is equal to 15 years.

As given,

Let x and y be the present age of Chole and Tino. respectively.

Combined age = 48

Given condition,

x + y = 48 _______(1)

Three years ago

x - 3 = 2y

⇒x =2y +3 _______(2)

Substitute the value of x in (1),

2y+3 +y =48

⇒ 3y = 45

⇒ y = 15years

Therefore , as given Chole and Tinos age , the present age of Tino is equal to 15 years.

Learn more about age here

brainly.com/question/3023145

#SPJ4

5 0
1 year ago
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