Data set A have a median of 2, mean of 3.4, min of 1 and max of 9. range of 8
Data set B have a median of 7, mean of 6, min of 1 and max of 12, range of 11
so Data set B is much bigger than data set A
Answer:
90
Step-by-step explanation:
90 Or, we can say that it is a method of breaking down the given integer into its prime factors. Therefore, the HCF of 18 and 45 is 9. Therefore, the HCF of 18 and 45 is 90.
Answer:
d.5/3
Step-by-step explanation:
m=y2-y1/x2-x1
m=8-3/9-6=5/3
A>70*9
a>360
a should be at least 361
