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4 years ago

10

Write an expression for an increased by 3

2 answers:

choli [55]4 years ago

8 0

Please explain. What do you mean by increased by 3? Do you mean something like "5 + 3 = 8"?

Airida [17]4 years ago

5 0

5x + 6
6 more than 5 times a number
Hope this is correct!

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Someone help me with all of this

Gre4nikov [31]

I’m working on the same thing in school! For number 2, what i would do is start by setting up the scatter plot by using the X and Y table and create origins to place on the graph. ( ex. (1,30) for your first one ). Also, remember to write in the laps completed and calories burned. Next, estimate a line that meets as many points as possible. ( I would use the completed scatter plot in number 3 for an example for how to draw the line ). And that’s all I can help you with :( I forgot how to do the equation part because I just started with this on Monday. Hope this helps!
-Taylor

4 0

3 years ago

For the following exercise, determine the range (possible values) of the random variable, . Wood paneling can be ordered in thic

dedylja [7]

Answer:

Range = 0.125

Step-by-step explanation:

The detailed steps is as shown in the attached file.

3 0

4 years ago

WILL GIVE BRAINLIEST!

Nataly [62]

Answer:

The equation the circle is given by

${\bf 4x}^{\bf 2}+{\bf 4y}^{\bf 2}-{\bf 8x+0y-60}={\bf 0}$

Step-by-step explanation:

The general form of the circle is

$x^2+y^2+Dx+Ey+F=0\hfill (1)$

Given points are (5,0) , (0,4) and (2,4)

Let the points (5,0) , (0,4) and (2,4) be (x_1,y_1) , (x_2,y_2) and (x_3,y_3) respectively

The equation of the circle passes through given points (5,0) , (0,4) and (2,4)

Substituting the point (5,0) in (1)

$(-5)^2+(0)^2+D(5)+E(0)+F=0$

$25-5D+F=0$

$5D-F=25\hfill (2)$

Substituting the point (0,4) in

$(0)^2+(4)^2+D(0)+E(4)+F=0$

$16+4E+F=0$

$4E+F=-16\hfill (3)$

Substituting the point (2,4) in

$(2)^2+(4)^2+D(2)+E(4)+F=0$

$4+16+2D+4E+F=0$

$2D+4E+F=-20\hfill (4)$

By solving the equations (2) ,(3) and(4) we get the values of D,E and F as below

$D=-2$ , $E=0$ and $F=-15$

substituting the values of D,E and F in (1) we get

$x^2+y^2-2x+(0)y-15=0$

Now multiplying the above equation into 4 we get

$4x^2+4y^2-8x+(0)y-60=0$

6 0

3 years ago

Plzzzzzzz help pppppppp

Pepsi [2]

Answer:

c

A

D

Step-by-step explanation:

i hope this helps

4 0

3 years ago

Simplify 6s^5t x s^4t^2. 6 points on the line please help me

Ghella [55]

Answer:

6s9t3

—————

x

Step-by-step explanation:

Step 1 :

t

Simplify —

x

Equation at the end of step 1 :

t

(((6 • (s5)) • —) • s4) • t2

x

Step 2 :

Equation at the end of step 2 :

t

(((2•3s5) • —) • s4) • t2

x

Step 3 :

Multiplying exponential expressions :

3.1 s5 multiplied by s4 = s(5 + 4) = s9

Equation at the end of step 3 :

6s9t

———— • t2

x

Step 4 :

Multiplying exponential expressions :

4.1 t1 multiplied by t2 = t(1 + 2) = t3

3 0

3 years ago