A Punnett square would help here.
Let's say (R) is dominant red and (r) is recessive red, aka yellow.
You start with F1 hybrid flowers that are all (Rr) - these are all <em>orange</em>. So when they reproduce, both parents are (Rr). When you create a Punnett square, you'll see that the results for the F2 generation are (RR), (rr), and (Rr) twice.
(RR) is red, (rr) is yellow, and (Rr) is orange, just like the F1 generation.
This is a trick question - there is no mitosis 2.
The correct answer is the bars range from tallest for very high concentration to shortest for very low concentration. Hope this helps.
Semiconductor materials are ostensibly little band hole encasings. The characterizing property of a semiconductor material with pollutions that adjust its electronic properties controllably. Most ordinarily utilized semiconductor materials are crystalline inorganic solids.
Answer:
d.0.48
Explanation:
When a population is in Hardy Weinberg equilibrium the <u>genotypic </u>frequencies are:
freq (AA) = p²
freq (Aa) = 2pq
freq (aa) = q²
<em>p</em> is the frequency of the dominant <em>A</em> allele and <em>q</em> is the frequency of the recessive <em>a</em> allele.
In this population of 100 individuals, 84 martians have the dominant phenotype and 16 have the recessive phenotype.
Therefore:
q²=16/100
q² = 0.16
q=√0.16
q = 0.4
And p+q=1, so:
p = 1 - q
p = 1-0.4
p = 0.6
The frequency of heterozygotes is:
freq (Aa) = 2pq = 2 × 0.4 × 0.6
freq (Aa) = 0.48