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Ksju [112]
3 years ago
14

Plz help cause idk what to do

Mathematics
1 answer:
mixer [17]3 years ago
8 0

Answer:

<em>-9.5 + 6x ≥ 42.1 </em>

<em>6x ≥ 51.6</em>

x ≥ 8.6

Here, we can see that x is greater than or equal to 8.6. So, we can say that 8.6 is the lowest value of x

but we have 2 options with 8.6 as the lowest term, we can see that the brackets are different in the beginning

the '[' bracket tells us to include 8.6 in the values of x whereas the '(' bracket tells to exclude 8.6 from the possible values of x

since we know that x is greater than or equal to 8.6, we will use the '[' bracket

Hence, b is your answer

<em></em>

<em>PS: i need one brainly to reach the next rank, if you find this answer helpful. Mark Brainliest </em>

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What is the area, in square centimeters, of the isosceles trapezoid below?
charle [14.2K]
Both triangles area:
4.2 x 8.2 = 34.44

you don’t need to divide by two cause there’s two triangles anyways.

also, you get 8.2 by subtracting the total length by the top length. (13.5-5.3)

rectangle:
4.2 x 5.3 = 22.26

the total area is 56.7cm squared
7 0
3 years ago
See attached picture, is there a way to enter equations or algebraic symbols?
coldgirl [10]

SOLUTIONS

Solve a given equations or algebraic symbols?

\begin{gathered} f(x)=x^2+2x \\ g(x)=1-x^2 \end{gathered}

(A)

\begin{gathered} (f+g)(x)=(x^2+2x)+(1-x^2) \\ collect\text{ like terms} \\ x^2-x^2+2x+1 \\ (f+g)(x^)=2x+1 \end{gathered}

(B)

\begin{gathered} (f-g)(x)=(x^2+2x)-(1-x^2) \\ =x^2+2x-1+x^2 \\ =x^2+x^2+2x-1 \\ (f-g)(x)=2x^2+2x-1 \end{gathered}

(C)

\begin{gathered} fg(x)=(x^2+2x)(1-x^2) \\ =x^2-x^4+2x-2x^3 \\ fg(x)=-x^4-2x^3+x^2+2x \end{gathered}

(D)

\begin{gathered} \frac{f}{g}(x)=(x^2+2x)\div(1-x^2) \\ =\frac{x^2+2x}{1-x^2} \end{gathered}

5 0
1 year ago
Two equations are given below:
stealth61 [152]

a is given to us so just plug a into the first equation:

b-3 - 3b =9

Add 3 to both sides:

b-3b=12

Combine like terms:

-2b=12

Divide by -2 to get b by itself:

b=-6

The only answer with b as -6 is the first one, (-9,-6)

8 0
3 years ago
Read 2 more answers
How do you solve for the quotient of (x^-1) - 1 ÷ x - 1?
Ber [7]

\bf x^{-1}-1\div x-1\implies \implies \cfrac{1}{x}-1\div x-1\implies \cfrac{\frac{1}{x}-1}{~~x-1~~}\implies \cfrac{~~\frac{1-x}{x}~~}{\frac{x-1}{1}} \\\\\\ \cfrac{1-x}{x}\cdot \cfrac{1}{x-1}\implies \cfrac{-(\begin{matrix} x-1 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix})}{x}\cdot \cfrac{1}{\begin{matrix} x-1 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}}\implies -\cfrac{1}{x}\implies -x^{-1}

3 0
3 years ago
Risk taking is an important part of investing. In order to make suitable investment decisions on behalf of their customers, port
GrogVix [38]

Answer:

a=49.5 -1.28*15=30.3

So the value of height that separates the bottom 10% of data from the top 90% is 30.3.  

If the score is lower than 30.3 we consider this score as risk averse

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the scores of a population, and for this case we know the distribution for X is given by:

X \sim N(49.5,15)  

Where \mu=49.5 and \sigma=15

We are interested in the bottom 10% of the data.

For this part we want to find a value a, such that we satisfy this condition:

P(X>a)=0.9   (a)

P(X   (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.  

As we can see on the figure attached the z value that satisfy the condition with 0.1 of the area on the left and 0.9 of the area on the right it's z=-1.28. On this case P(Z<-1.28)=0.1 and P(z>-1.28)=0.9

If we use condition (b) from previous we have this:

P(X  

P(z

But we know which value of z satisfy the previous equation so then we can do this:

z=-1.28

And if we solve for a we got

a=49.5 -1.28*15=30.3

So the value of height that separates the bottom 10% of data from the top 90% is 30.3.  

If the score is lower than 30.3 we consider this score as risk averse

7 0
3 years ago
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