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Vesnalui [34]
3 years ago
12

PLEASE HELP ASAP!!!! 15 POINTS! AND I WILL GIVE BRAINLIEST!!!!

Mathematics
2 answers:
pochemuha3 years ago
7 0

Answer:

9

Step-by-step explanation:

Anuta_ua [19.1K]3 years ago
4 0

Answer:

the answer is for your question is 9

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A high school student has started a new job. He plans to save $1 the first week, $2 the second week, $4 the third week, and $8 t
Mama L [17]
If you already know that you have . . . 

1$ after week 1
2$ after week 2
4$ after week 3
8$ after week 4

 . . . You can then tell that every week the money you save doubles (times 2) 

So to continue . . . . 
16$ after week 5
32$ after week 6
64$ after week 7
128$ after week 8
256$ after week  9
512$ after week 10 

You will then know that after ten weeks u will have 512$ which is answer choice D. 

Hope this helps! :)

3 0
3 years ago
Read 2 more answers
1/f - 1/u = 1/v then f
german

Answer:

1/V

Step-by-step explanation:

8 0
3 years ago
Find x, if the distance end points is (x,1) and (4,4) with the total distance is the square root of 10.
Alex Ar [27]
Okay, take a look at diagram 1 (I know it's rubbish I did it on paint :D), this shows all the information you've given in the question. The two coordinates and the distance between them.

Now if we draw additional lines on this diagram, we can make a right-angled triangle (this is on diagram 2). We can also work out the lengths of the additional sides because we know both coordinates at the end-points of the additional lines.

Finally because this is a right-angled triangle, Pythagoras' theorem must apply to its sides meaning
( \sqrt{10} )^2 = (x-4)^2 + 3^2
10 = (x-4)^2 + 9
(x-4)^2 = 1 \Rightarrow x-4 = 1
therefore x=5.

3 0
3 years ago
Find a formula for the distance from the point​ P(x,y,z) to each of the following planes. a. Find the distance from​ P(x,y,z) to
BARSIC [14]

Answer:

Distance to the xy-plane = |z|

Distance to the yz-plane = |x|

Distance to the xz-plane = |y|

Step-by-step explanation:

The distance from P(x,y,z) to the xy-plane is by definition the magnitude of the vector that goes from the perpendicular projection of P over the xy-plane to the point P, which is exactly the magnitude of the vector (0,0,z) = |z| the absolute value of z

Similarly, the distance from P to the yz-plane is |x| and the distance from P to the xz-plane is |y|

Distance to the xy-plane = |z|

Distance to the yz-plane = |x|

Distance to the xz-plane = |y|

7 0
3 years ago
The following are quiz scores: 85, 88, 89, 96, 91, 77, 79, 98, 86, 99. What is the standard deviation of the given test scores?
ArbitrLikvidat [17]

Answer:

7.1

Step-by-step explanation:

- Find mean

- For each number you subtract the mean and square the result.

- Work out the mean of those squared differences and find square root of that.

- Hope that helped! Let me know if you need further explanation.

5 0
3 years ago
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