The symbol between the x and 2y is missing. If it is a plus sign, then
Anything parallel to x+2y = 4 is going to be of the form x+2y = C where C is some fixed number. The left side stays identical and unchanged. To find the value of C, we plug in (x,y) = (0,0). So replace x with 0 and replace y with 0
x+2y = C
0+2*0 = C
0 + 0 = C
0 = C
C = 0
So the equation of the parallel line is x+2y = 0
Again this is all hinged on the assumption that there is a plus sign between x and 2y
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If the symbol between the x and 2y is a minus sign then
Anything parallel to x-2y = 4 is in the form x-2y = C where C is a constant
Plug in (x,y) = (0,0)
x-2y = C
0 - 2*0 = C
0 - 0 = C
0 = C
C = 0
So the parallel equation is x-2y = 0 only if the symbol between the x and 2y is a minus sign.
F(x) = -(x + 8)² - 1
<span>The function (not its graph) decreases on interval [-8, ∞). It is a quadratic function in vertex form. That form makes it easy to pick out the one extremum, where x equals -8. The leading coefficient is negative, so the extremum must be a maximum. The function decreases as x increases from there. </span>
<span>Notice that I include the value -8 in the interval. The function does not have instantaneous decrease at that value, but that is not what it means for a function to be decreasing over an interval. </span>
<span>Let a and b be any two values on [-8, ∞), such that a < b. </span>
<span>-8 ≤ a < b </span>
<span>Then f(a) > f(b). Therefore, function f is decreasing on interval [-8, ∞).</span>
If u you do the slope formula...(m=y2-y1/x2-x1)
2-4/5-8
-2/-3=2/3
Therefore the slope would be 2/3
Btw can u plz mark this answer the brainliest
Answer:
4(-7)
4*-7=-28
Whenever multiplying +positive sign and -negative sign= -negative sign