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Natali5045456 [20]
4 years ago
14

Lori is running a marathon, which is 26.2 miles long. So far, she has run one-tenth of the marathon. How far has Lori run? (from

the book)
Mathematics
2 answers:
mars1129 [50]4 years ago
4 0
She has 23.58 miles left to run because you multiply 26.2×0.1 and get 23.58.
myrzilka [38]4 years ago
3 0
To find how long Lori has run do 1/10 x 26.2
1/10 x 131/5
= (1x131) / (10x5)
= 131/50 or 2 and 31/50 miles long
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The diagonal of a rhombus are 8 cm 6 cm long. What is the area of the rhombus​
IRINA_888 [86]
The area of a rhombus can be found by using the formula:

A = (1/2)(d1)(d2)

Area = (1/2)(8)(6)

Area = 24 cm^2

Your other option is to remember that in a rhombus the diagonals bisect each other, and form right triangles. So you have 4 right triangles each with sides of 4 cm (1/2 of 8 cm) and 3 cm (1/2 of 6 cm). 4 x [(1/2) x (4)(3)] = 4 x 6 = 24 cm^2.
7 0
3 years ago
What is 4X +9 equals 5X -2
Vlad [161]

Answer:

X=11

Step by step:

4x+9=5x-2

+2 to both sides

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6 0
3 years ago
Read 2 more answers
30 POINTS HELP IM LITERALLY SO DUM
Aliun [14]

Answer:

b. 6

Step-by-step explanation:

I'm not 100% sure if this is the answer but here was my thinking process:

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7 0
2 years ago
A population has the following characteristics.(a) A total of 25% of the population survives the first year. Of that 25%, 75% su
zaharov [31]

Answer:

After 1st year, the age distribution will be

x_1 = \left[\begin{array}{ccc}1584\\36\\108\end{array}\right]

After 2nd year, the age distribution will be

x_2 = \left[\begin{array}{ccc}5256\\396\\27\end{array}\right]

Step-by-step explanation:

A population has the following characteristics.

A total of 25% of the population survives the first year. Of that 25%, 75% survives the second year.

The average number of offspring for each member of the population is 3 the first year, 5 the second year, and 3 the third year.

From the above information, we can construct a transition age matrix.

A = \left[\begin{array}{ccc}3&5&3\\0.25&0&0\\0&0.75&0\end{array}\right]

The population now consists of 144 members in each of the three age classes.

From the above information, we can construct the current age matrix.

x = \left[\begin{array}{ccc}144\\144\\144\end{array}\right]

How many members will there be in each age class in 1 year?

After 1st year, the age distribution will be

x_1 = A \cdot x

x_1 = \left[\begin{array}{ccc}3&5&3\\0.25&0&0\\0&0.75&0\end{array}\right] \times \left[\begin{array}{ccc}144\\144\\144\end{array}\right]

The matrix multiplication is possible since the number of columns of first matrix is equal to the number of rows of second matrix.

x_1 = \left[\begin{array}{ccc}1584\\36\\108\end{array}\right]

After 2nd year, the age distribution will be

x_2 = A \cdot x_1

x_2 = \left[\begin{array}{ccc}3&5&3\\0.25&0&0\\0&0.75&0\end{array}\right] \times \left[\begin{array}{ccc}1584\\36\\108\end{array}\right]

x_2 = \left[\begin{array}{ccc}5256\\396\\27\end{array}\right]

4 0
4 years ago
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Musya8 [376]

Answer:

339.35

Step-by-step explanation:

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