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lisov135 [29]
3 years ago
11

A rocket travels in a trajectory given by the equation s = -4.9t 2 + v0t, where s is meters above ground, t is time in seconds a

nd v0 is the initial velocity. If the intial velocity is 49 m/sec, after how many seconds will the rocket reach its maximum height?
Mathematics
1 answer:
Reptile [31]3 years ago
5 0

Step-by-step explanation:

s = -4.9t² + 49t

The vertex of the parabola is at t = -b/(2a).

t = -49 / (2 × -4.9)

t = 5

The rocket reaches its maximum height after 5 seconds.

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1/2expand the equation 1/2(3+4t-10)=
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\frac{1}{2} (3 + 4t - 10)

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2 years ago
Last year the robotics club had 30 members. This year the club has 24 members. Find the percent change in the number of members.
Naddika [18.5K]

Answer:

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Step-by-step explanation:

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3 years ago
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Which scatter plots shows a nonlinear association
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Answer:

Graph B.

Step-by-step explanation:

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8 0
2 years ago
Trigonometry
Natasha_Volkova [10]

Answer:

Step-by-step explanation:

For a triangle the area is

A=\frac{1}{2}bh

If our triangle is isosceles and the 2 congruent sides each measure 4 and they include an angle of 40 degrees, let's say that the vertex angle is 40 and the sides that are not the base each measure 4.  If we drop an altitude from the vertex to the base, we cut the triangle into 2 right triangles, with the vertex angle being 20 degrees and the hypotenuse being 4.  To find the base, then, which is opposite the angle, we use the sin ratio:

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4sin(20) = b so

b = 1.368

But we need the whole base, and that is only half of it.  So

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To find the height, which is adjacent to the angle, we use the cos ratio:

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A = 5 meters squared.

7 0
2 years ago
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