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lisov135 [29]
3 years ago
11

A rocket travels in a trajectory given by the equation s = -4.9t 2 + v0t, where s is meters above ground, t is time in seconds a

nd v0 is the initial velocity. If the intial velocity is 49 m/sec, after how many seconds will the rocket reach its maximum height?
Mathematics
1 answer:
Reptile [31]3 years ago
5 0

Step-by-step explanation:

s = -4.9t² + 49t

The vertex of the parabola is at t = -b/(2a).

t = -49 / (2 × -4.9)

t = 5

The rocket reaches its maximum height after 5 seconds.

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muminat
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S=999+997+995+\cdots+5+3+1
\implies 2S=(1+999)+(3+997)+(5+995)+\cdots+(995+5)+(997+3)+(999+1)

2S=\underbrace{1000+1000+\cdots+1000+1000}_{500\text{ times}}

(We are adding 500 instances of 1000 because that's how many odd numbers there are between 1 and 1000, inclusive.)

2S=500\times1000=500000
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What is the fully factored form of the expression 16x^2 - 49y^2
podryga [215]

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(4x + 7y)(4x - 7y)

Step-by-step explanation:

Rewrite 16 as 4^2

= 4^2x^2 - 49y^2

Rewrite 49 as 7^2

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Apply the Exponent Rule Pt 1  ((a^m*b^m =(ab)^m))

= (4x)^2 - 7^2y^2

Apply the Exponent Rule Pt 2

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Apply Difference of Squares Formula (( x^2-y^2 = (x + y)(x - y)

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Answer:

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Step-by-step explanation:

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Answer:

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therefore x = 4

5 0
2 years ago
Read 2 more answers
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