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3 years ago

Edge: Which equation has a focus at (–6, 12) and directrix of x = –12?

Mathematics

2 answers:

Volgvan3 years ago

8 0

Answer:

C) (y - 12)^2 = 12(x+9)

inysia [295]3 years ago

7 0

Answer:

Its C

Step-by-step explanation:

I got it right on edge

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Evaluate 8 - 4.7y - x <br> when y= -1 and x= 2.

Marat540 [252]

Substitute in the values for y and x into the equation.

so..

8 - 4.7(-1) - (2) solve the equation
8 + 4.7 -2
12.7 - 2
10.7

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3 years ago

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Help what’s the answer

Setler79 [48]

It’s A, D and E

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2 years ago

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Please help me on the second one. I do not know the answer

Lapatulllka [165]

Answer:

Step-by-step explanation:

Just input 3 instead of x, you would get 14(3) + 21 = 63

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3 years ago

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What is the factorizaion of the polynomial graphed below? assuming it has no constant factor.

Oxana [17]

Answer:

y = 0.96(x -√5)(x + √5).

Step-by-step explanation:

The two zeros of this polynomial are (0, 0) and (5, 0), and the vertex is (2.5, -6), all of this info readily available from the graph.

The standard equation of a vertical parabola with vertex at (h, k) is

y - k = a(x - h)^2, where the vertex is represented by (h, k). Since we know that the vertex is (2.5, -6), the equation for the given graphed parabola is

y + 6 = a(x - 2.5)^2

Since the graph of this parabola goes through the origin, (0, 0), the following must be true if we substitute 0 for both x and y:

0 + 6 = a(0 - 2.5)^2, or 6 = a(6.25). Thus, a = 6/6.25, or a = 0.96.

The equation of this polynomial must then be:

y + 6 = 0.96(x - 2.5)^2, which is satisfied by both (0, 0) and (5, 0).

This equation can be rewritten as

y = 0.96(x^2 - 5x + 6.25) - 6 = 0.96x^2 - 4.8x + 6 - 6, or just

y = 0.96x^2 - 4.8x. We must factor this. Factoring out 0.96, we get:

y = 0.96(x^2 - 5), which can be factored further:

y = 0.96(x -√5)(x + √5). This is the fully factored form of the polynomial.

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3 years ago

Which is equivalent to V180x11 after it has been simplified completely?

inna [77]

Question:

Which is equivalent to $\sqrt{180x^{11}}$ after it has been simplified completely?

Answer:

$\sqrt{180x^{11}} = 6x^{5}\sqrt{5x}$

Step-by-step explanation:

Given

$\sqrt{180x^{11}}$

Required

Simplify

We start by splitting the square root

$\sqrt{180x^{11}} = \sqrt{180} * \sqrt{x^{11}}$

Replace 180 with 36 * 5

$\sqrt{180x^{11}} = \sqrt{36 * 5} * \sqrt{x^{11}}$

Further split the square roots

$\sqrt{180x^{11}} = \sqrt{36} *\sqrt{5} * \sqrt{x^{11}}$

$\sqrt{180x^{11}} = 6*\sqrt{5} * \sqrt{x^{11}}$

Replace power of x; 11 with 10 + 1

$\sqrt{180x^{11}} = 6*\sqrt{5} * \sqrt{x^{10 + 1}}$

From laws of indices; $a^{m+n} = a^m * a^n$

So, we have

$\sqrt{180x^{11}} = 6*\sqrt{5} * \sqrt{x^{10} * x^1}$

$\sqrt{180x^{11}} = 6*\sqrt{5} * \sqrt{x^{10} * x}$

Further split the square roots

$\sqrt{180x^{11}} = 6*\sqrt{5} * \sqrt{x^{10}} * \sqrt{x}$

From laws of indices; $\sqrt{a} = a^{\frac{1}{2}}$

So, we have

$\sqrt{180x^{11}} = 6*\sqrt{5} * x^{10*\frac{1}{2}} * \sqrt{x}$

$\sqrt{180x^{11}} = 6*\sqrt{5} * x^{\frac{10}{2}} * \sqrt{x}$

$\sqrt{180x^{11}} = 6*\sqrt{5} * x^{5} * \sqrt{x}$

Rearrange Expression

$\sqrt{180x^{11}} = 6 * x^{5} * \sqrt{5} * \sqrt{x}$

$\sqrt{180x^{11}} = 6x^{5} * \sqrt{5} * \sqrt{x}$

From laws of indices; $\sqrt{a} *\sqrt{b} = \sqrt{a*b} = \sqrt{ab}$

So, we have

$\sqrt{180x^{11}} = 6x^{5} * \sqrt{5*x}$

$\sqrt{180x^{11}} = 6x^{5} * \sqrt{5x}$

$\sqrt{180x^{11}} = 6x^{5}\sqrt{5x}$

<em>The expression can no longer be simplified</em>

Hence, $\sqrt{180x^{11}}$ is equivalent to $6x^{5}\sqrt{5x}$

7 0

3 years ago

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