Answer:
1) (c)∠ G = 34°
2) (a) x = 33°
3) (d) The perpendicular segments are JM, KL, PQ AND NR.
Step-by-step explanation:
Here in the given questions:
1) p II r
⇒ ∠ G = 34° (ALTERNATE EXTERIOR ANGLES)
Hence, the measure of ∠ G = 34°
2) In the given triangle:
The measure of exterior angle is always the sum of interior opposite angles.
⇒ Here, x + 72° = 105°
or, x = 105° - 72° = 33° , or x = 33°
3) The given plane in the cube is JKPN
The segments which have J , K , P and N as their one vertex are perpendicular to the given plane.
Hence, the segments are JM, KL, PQ AND NR.
The area of a circle of radius r is pi*r^2
Hence here the area is A=5^2*pi=25pi~78.5 square inches
I think it’s c or b but I’m positive it’s b
Answer:
Step-by-step explanation:
∠A = arctan(33/43) ≈ 37.5°
AB = √(43² + 33²) = √2938
Law of Sines
∠C = arcsin(sinA ⋅ AB/BC) ≈ 34.7°
Answer:
Step-by-step explanation:
we have
step 1
Solve (90+1)
step 2
Solve 0.0698(91)
step 3
Solve sin (6.3518)
step 4
Solve 105(0.11063)
step 5
Solve 11.616 + 105
