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scZoUnD [109]
4 years ago
14

The distance between the points (-3,-1) and (-4,0) is the square root of ___?

Mathematics
1 answer:
Galina-37 [17]4 years ago
6 0
\bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%  (a,b)
&({{ -3}}\quad ,&{{ -1}})\quad 
%  (c,d)
&({{ -4}}\quad ,&{{0}})
\end{array}\qquad 
%  distance value
d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}
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Is the relation { (5, 2), (-1, 6), (8, -2), (5, 3)} a function? why or why not? list the domain and range
Tasya [4]

Answer:

it is not a function because the input 5 (x) has more than one output (y)

domain (5,-1,8)

range (2,6,-2,3)

Step-by-step explanation:

5 0
3 years ago
using the 28/36 ratio, determine the maximum allowable recurring debt for someone with an annual income of $86,250.
murzikaleks [220]
Given:
28/36 ratio
annual income: 86,250

28+36 = 64

28/64 * 86,250 = 0.4375 * 86,250 = 37,734.375
36/64 * 86,250 = 0.5625 * 86,250 = 48,515.625

28/36 ⇒ 37,734.375/48,515.625
5 0
3 years ago
100 points! Mhanifa can you please help? Look at the picture attached. I will mark brainliest!
dimulka [17.4K]

Answer:

1 and 2.

Midpoints calculated, plotted and connected to make the triangle DEF, see the attached.

  • D= (-2, 2), E = (-1, -2), F = (-4, -1)

3.

As per definition, midsegment is parallel to a side.

Parallel lines have same slope.

<u>Find slopes of FD and CB and compare. </u>

  • m(FD) = (2 - (-1))/(-2 -(-4)) = 3/2
  • m(CB) = (1 - (-5))/(1 - (-3)) = 6/4 = 3/2
  • As we see the slopes are same

<u>Find the slopes of FE and AB and compare.</u>

  • m(FE) = (-2 - (- 1))/(-1 - (-4)) = -1/3
  • m(AB) = (1 - 3)/(1 - (-5)) = -2/6 = -1/3
  • Slopes are same

<u>Find the slopes of DE and AC and compare.</u>

  • m(DE) = (-2 - 2)/(-1 - (-2)) = -4/1 = -4
  • m(AC) = (-5 - 3)/(-3 - (-5)) = -8/2 = -4
  • Slopes are same

4.

As per definition, midsegment is half the parallel side.

<u>We'll show that FD = 1/2CB</u>

  • FD = \sqrt{(2+1)^2+(-2+4)^2} = \sqrt{3^2+2^2} = \sqrt{13}
  • CB = \sqrt{(1 + 5)^2+(1+3)^2} = \sqrt{6^2+4^2} = 2\sqrt{13}
  • As we see FD = 1/2CB

<u>FE = 1/2AB</u>

  • FE = \sqrt{(-4+1)^2+(-1+2)^2} = \sqrt{3^2+1^2} = \sqrt{10}
  • AB = \sqrt{(-5 -1)^2+(3-1)^2} = \sqrt{6^2+2^2} = 2\sqrt{10}
  • As we see FE = 1/2AB

<u>DE = 1/2AC</u>

  • DE = \sqrt{(-2+1)^2+(2+2)^2} = \sqrt{1^2+4^2} = \sqrt{17}
  • AC = \sqrt{(-5 +3)^2+(3+5)^2} = \sqrt{2^2+8^2} = 2\sqrt{17}
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3 0
3 years ago
Read 2 more answers
A jet travels from chicago to kansas city at a speed of 440 knots. If it takes a plane 3 hr longer to fly from kansas city to ch
steposvetlana [31]

d = distance between the two cities

v₁ = average speed while going from chicago to kansas city = 440 knots

t₁ = time taken to travel distance going from chicago to kansas city

time taken to travel distance going from chicago to kansas city is given as

t₁ = d/v₁

t₁ = d/440                                        eq-1


v₂ = average speed while going from kansas city to chicago = 110 knots

t₂ = time taken to travel distance going from kansas city to chicago

time taken to travel distance going from kansas city to chicago is given as

t₂ = d/v₂

t₂ = d/110                                                     eq-2


Given that :

t₂ = t₁ + 3

using eq-1  and eq-2

(d/110) = (d/440) + 3

d = 440

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Elina [12.6K]
The simplest for of 15/25 is 3/5
6 0
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