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sasho [114]
3 years ago
11

Write the pair of fractions 3/10 and 1/2 as a pair of fractions with a common denominator

Mathematics
1 answer:
spin [16.1K]3 years ago
7 0
The commen denominator for 10 and 2 would be 10. so 3/10 will stay the same ... and now we change the 1/2 to a fraction that has its denominator as 10. so the new fractions would be ... 3/10, and 5/10.
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Dixon shadow is 9 feet long Adriana shadow is 6 feet long if Dixon is 6 feet tall how tall is Adriana
kolbaska11 [484]
Adriana would be 3 feet tall because theyre both the 3feet of difference.
8 0
3 years ago
A county is considering rasing the speed limit on a road because they claim that the mean speed of vehicles is greater than 30 m
DochEvi [55]

Answer:

No, at alpha equals 0.10​, we do not have enough evidence to support the​ county's claim.

Step-by-step explanation:

We are given that a county is considering raising the speed limit on a road because they claim that the mean speed of vehicles is greater than 30 miles per hour.

A random sample of 15 vehicles has a mean speed of 31 miles per hour and a standard deviation of 4.7 miles per hour.

<em><u>Let </u></em>\mu<em><u> = true mean speed of the vehicles.</u></em>

SO, <u>Null Hypothesis</u>, H_0 : \mu \leq  30 miles per hour   {means that the mean speed of vehicles is lesser than or equal to 30 miles per hour}

<u>Alternate Hypothesis,</u> H_A : \mu > 30 miles per hour   {means that the mean speed of vehicles is greater than 30 miles per hour}

The test statistics that will be used here is <u>One-sample t test statistics</u> as we don't know about the population standard deviation;

                        T.S.  = \frac{\bar X -\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean speed of 15 vehicles = 31 mph

             s = sample standard deviation = 4.7 mph

             n = sample of vehicles = 15

So, <em><u>test statistics</u></em>  =   \frac{31-30}{\frac{4.7}{\sqrt{15} } }  ~ t_1_4

                               =  0.824

<u><em>Hence, the value of test statistics is 0.824.</em></u>

<em />

<em>Now at 0.10 significance level, the t table gives critical value of 1.345 at 14 degree of freedom for right-tailed test. Since our test statistics is less than the critical value of t as 0.824 < 1.345, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region.</em>

<em />

Therefore, we conclude that the mean speed of vehicles is lesser than or equal to 30 miles per hour which means that the county's claim is not supported.

4 0
3 years ago
Simplify the radical completely.
AlladinOne [14]

Answer:

D

Step-by-step explanation:

\sqrt{300}  =  \sqrt{100 \times 3}  =  \sqrt{100}  \times  \sqrt{3}  = 10 \sqrt{3}

3 0
2 years ago
Brown ball weighed 1.6 pounds and the green ball weighed 0.39 pounds if he placed both on the scale at the same time what will t
NemiM [27]

1.6+0.39 which is 1.99 pounds.

8 0
3 years ago
Whitey calved an 87-pound calf on March 8. The calf was sold 245 days later
miskamm [114]
515 - 87 = 428
428/245 = 1.746938
To the nearest tenth = 1.7 lbs
4 0
3 years ago
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