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NARA [144]
2 years ago
12

The area (A) of a rectangle varies jointly as the length (l) and the width (w), and whose A = 60 sq. cm when l = 4 cm and w = 3

cm. What is the area of rectangle if the length is 6 cm and whose width is 3 cm? ​
Mathematics
1 answer:
s2008m [1.1K]2 years ago
8 0

Answer:

The area is 90 sq. cm

Step-by-step explanation:

Given

The variation can be represented as:

A\ \alpha\ l * w

Area = 60, when l = 4 and w = 3

Required

Find Area, when l = 6 and w = 3

Represent the variation as an equation

A = k(l * w)

Where k is the constant of variation.

Substitute 60 for A, 4 for l and 3 for w

60 = k * (4 * 3)

60 = k * 12

Make k the subject

\frac{60}{12} = k

5=k

k=5

To get the value of Area when l = 6 and w = 3.

Substitute 5 for k, 6 for l and 3 for w in A = k(l * w)

A = 5 * 6 * 3

A = 90

<em>The area is 90 sq. cm</em>

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Complete Question

From a random sample of size 18, a researcher states that (11.1, 15.7) inches is a 90% confidence interval for mu, the mean length of bass caught in a small lake. A normal distribution was assumed. Using the 90% confidence interval obtain:

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b

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Step-by-step explanation:

From the question we are told that

  The sample size is  n = 18

  The 90% confidence interval is  (11.1, 15.7)

Generally the point estimate of  \mu is mathematically  evaluated  as

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Generally the margin of error is mathematically evaluated  as

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   Z_{\frac{\alpha }{2} } =  1.645

Generally the equation for the lower limit of the confidence interval is  

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  From the question we are told the confidence level is  95% , hence the level of significance is    

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=>   \alpha = 0.05

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Generally the margin of error is mathematically represented as  

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Generally 95% confidence interval is mathematically represented as  

      \= x -E <  \mu <  \=x  +E

=>    13.4  -  2.7  <  \mu < 13.4  +   2.7

=>    10.7 <  \mu < 16.1

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