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NARA [144]
2 years ago
12

The area (A) of a rectangle varies jointly as the length (l) and the width (w), and whose A = 60 sq. cm when l = 4 cm and w = 3

cm. What is the area of rectangle if the length is 6 cm and whose width is 3 cm? ​
Mathematics
1 answer:
s2008m [1.1K]2 years ago
8 0

Answer:

The area is 90 sq. cm

Step-by-step explanation:

Given

The variation can be represented as:

A\ \alpha\ l * w

Area = 60, when l = 4 and w = 3

Required

Find Area, when l = 6 and w = 3

Represent the variation as an equation

A = k(l * w)

Where k is the constant of variation.

Substitute 60 for A, 4 for l and 3 for w

60 = k * (4 * 3)

60 = k * 12

Make k the subject

\frac{60}{12} = k

5=k

k=5

To get the value of Area when l = 6 and w = 3.

Substitute 5 for k, 6 for l and 3 for w in A = k(l * w)

A = 5 * 6 * 3

A = 90

<em>The area is 90 sq. cm</em>

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The cost of 1 chocolate cake is $ 6 and cost of 1 vanilla cake is $ 7

<em><u>Solution:</u></em>

Let "c" be the cost of 1 chocolate cake

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Therefore, we can frame a equation as:

14 x cost of 1 chocolate cake + 5 x cost of 1 vanilla cake = 119

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Therefore, we can frame a equation as:

10 x cost of 1 chocolate cake + 10 x cost of 1 vanilla cake = 130

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<em><u>Let us solve eqn 1 and eqn 2</u></em>

Multiply eqn 1 by 2

28c + 10v = 238 ------ eqn 3

<em><u>Subtract eqn 2 from eqn 3</u></em>

28c + 10v = 238

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( - ) --------------------------

18c = 108

c = 6

<em><u>Substitute c = 6 in eqn 1</u></em>

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84 + 5v = 119

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