3 years ago

What are 3 equivalent ratios to 3:11

Mathematics

1 answer:

Helen [10]3 years ago

6 0

Answer:

three equivalent ratios will be

6:22 , 9:33, 15:55

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M<br> /<br> n<br> (x), x not equal to

azamat

Answer:

In M/n(x) x cannot be 0

Step-by-step explanation:

If any number is divided by 0, then that number is undefined and has no answer, so in math this is always avoided by not dividing with 0.

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3 years ago

Find the probability that the hitter makes 10 outs in 10 consecutive at-bats, assuming at-bats are independent events. Hint:

emmainna [20.7K]

Answer:

0.037

Step-by-step explanation:

If the hitter makes an out 72% of the time, then the probabilty that he makes hit in 1 at-bat is $p=0.72$ and the probabilty that he doesn't make hit in 1 at-bat is $q=1-p=1-0.72=0.28.$

The probability that the hitter makes 10 outs in 10 consecutive at-bats, assuming at-bats are independent events is

$P=p^{10}=(0.72)^{10}\approx 0.037.$

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3 years ago

You are standing 15 feet away from your friend's apartment building and look to see your friend at an angle of elevation of 72º.

Maksim231197 [3]

Answer:

15arctan(72°)

Step-by-step explanation:

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2 years ago

a spinner has 36 equal sections numbered from 1 to 36. what is the probability of the spinner landing on a number greater than 2

SCORPION-xisa [38]

Answer:

56% - 44%

Step-by-step explanation:

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3 years ago

In a nursery class of 18 pupils, the average is 4<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B2%7D%20" id="TexFormula1"

Alisiya [41]

Answer:

The sum of ages of all 18 pupils in the class = 81

Step-by-step explanation:

Total number of pupil in the class = 18

Average of years in the class = $4\frac{1}{2}$

Now, $4\frac{1}{2} = 4 + \frac{1}{2} = 4 + 0.5 = 4.5$

⇒Average of sum of ages in the class = 4.05

Let us assume the sum of ages of all students in the class = m

By the formula for AVERAGE:

$\textrm{Average of n obseravtions} = \frac{\textrm{Sum of n observations}}{\textrm{n}}$

$\implies 4.5 = \frac{m}{18}$

or, m = 18 x 4.5 = 81

Hence, the sum of ages of all 18 pupils in the class = 81

6 0

3 years ago

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