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2 years ago

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Jasmine sells bracelets at a local jewelry store in South Dekalb Mall. She has 1,190 purple beads and 2,125 pink beads. Each bra

celet can hold 85 beads, how many bracelets can she make

1 answer:

jeka57 [31]2 years ago

8 0

Answer:

39

Step-by-step explanation:

1190 + 2125 = 3315 (number of beads)

3315/85 = 36 (number of bracelets jasmine can make)

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Suppose that an internal report submitted to the managers at a bank in Boston showed that with 95 percent confidence, the propor

Dmitry [639]

Answer:

The sample size used to compute the 95% confidence interval is 1066.

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for population proportion is:

$CI=\hat p\pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}$

The 95% confidence interval for proportion of the bank's customers who also have accounts at one or more other banks is (0.45, 0.51).

To compute the sample size used we first need to compute the sample proportion value.

The value of sample proportion is:

$\hat p=\frac{Upper\ limit+Lower\ limit}{2}=\frac{0.45+0.51}{2}=0.48$

Now compute the value of margin of error as follows:

$MOE=\frac{Upper\ limit-Lower\ limit}{2}=\frac{0.51-0.45}{2}=0.03$

The critical value of <em>z</em> for 95% confidence level is:

$z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96$

Compute the value of sample size as follows:

$MOE=z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}\\0.03=1.96\times \sqrt{\frac{0.48(1-0.48)}{n}}\\(\frac{0.03}{1.96})^{2}=\frac{0.48(1-0.48)}{n}\\n=1065.404\\n\approx1066$

Thus, the sample size used to compute the 95% confidence interval is 1066.

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Is 0.212121212121...a rational number because a irrational number does not terminate or repeat?

pentagon [3]

The 21 part repeats

it can be represented as 21/99

it's rational

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The company has 5 employees, who earn a total of $1,000 each working day. They are paid each Monday for their work in the five-d

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ikadub [295]

12.2 is a rational number because you can write it as a fraction.
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Lady_Fox [76]

Answer:

DFE

Step-by-step explanation:

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