Find three consecutive integers such that the product of the first and third is 5 greater than 5 times the second.
1 answer:
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The figure depicting the board game is attached below.
Answer:
Step-by-step explanation:
Kindly note that selections done without replacement.
Count of numbers on the board game = 8
Count of odd numbers = (1, 9, 1) = 3
Count of digit 6 = 3
Probability = required outcome / Total possible outcomes
P(picking an odd number) = 3 / 8
Without replacement
Numbers left on board game = 8 - 1 = 7
P(picking a 6) = 3 / 7
Hence,
P(picking an odd number then, a 6) = 3/8 * 3/7 = 9 / 56
Question: What is 16% of 80?
You have to change the percentage to a decimal.
Remove the percentage sign and divide by 100 (% are based off 100)
16%⇒.16
Now multiply .16 and 80
Answer: 12.8
You have to change the percentage to a decimal.
Remove the percentage sign and divide by 100 (% are based off 100)
16%⇒.16
Now multiply .16 and 80
Answer: 12.8
Answer:
Infinite many solutions. Any x-value can satisfy the equation.
Step-by-step explanation:
Let's work on simplifying the equation a little to investigate which x-values satisfy it. Start by combining like terms on the left side (6x +4x=10x),
then distribute the factor "10" into the binomial (x+10), obtaining 10x +30.
Now we have the same expression on the left and the right of the equal sign:
10x +30=10x+30. We may subtract 30 from both sides, and obtain 10x=10x, and at this point divide by 10 both sides, and we obtain: x=x
The process is shown below.
x=x is an equation that is verified by absolutely ANY x value on the number line, and there are infinite x-values in the number line.
Therefore there are infinite many solutions to this equation (any x-value will satisfy it).