Find three consecutive integers such that the product of the first and third is 5 greater than 5 times the second.
1 answer:
Answer:
Step-by-step explanation:
3 consecutive integers....
1st integer = x
2nd integer = x + 1
3rd integer = x + 2
the product of 1st and 3rd is 5 greater then 5 times the 2nd...
x(x+2) = 5(x + 1) + 5
x^2 + 2x = 5x + 5 + 5
x^2 + 2x = 5x + 10
x^2 + 2x - 5x - 10 = 0
x^2 - 3x - 10 = 0
(x - 5)(x + 2) = 0
x - 5 = 0 x + 2 = 0
x = 5 x = -2
so it will be : 5,6,and 7 or -2,-1, and 0
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