Answer:
The solutions are x = 1.24 and x = -3.24
Step-by-step explanation:
Hi there!
First, let´s write the equation:
log[(x² + 2x -3)⁴] = 0
Apply the logarithm property: log(xᵃ) = a log(x)
4 log[(x² + 2x -3)⁴] = 0
Divide by 4 both sides
log(x² + 2x -3) = 0
if log(x² + 2x -3) = 0, then x² + 2x -3 = 1 because only log 1 = 0
x² + 2x -3 = 1
Subtract 1 at both sides of the equation
x² + 2x -4 = 0
Using the quadratic formula let´s solve this quadratic equation:
a = 1
b = 2
c = -4
x = [-b± √(b² - 4ac)]/2a
x = [-2 + √(4 - 4(-4)·1)]/2 = 1.24
and
x = [-2 - √(4 - 4(-4)·1)]/2 = -3.24
The solutions are x = 1.24 and x = -3.24
Have a nice day!
Answer:
<h2>The solution is -9 < x < 17.</h2>
Step-by-step explanation:
|x-4|<13.
The above equation means, whatever the actual value of x is, the value of (x - 4) must be greater than - 13 and less than 13.
Hence, -13 < x - 4 < 13 or, -9 < x < 17. The value of x will be in between -9 and 17. The value of x can not be -9 or 17.
20 p + 5p
10 p + 10p + 5p
10p + 10p + 1p + 1p + 1p +1p +1p
20p + 1p + 1p + 1p + 1p + 1p
2p + 2p + 2p + 2p + 2p + 2p +2p +2p + 2p + 2p + 2p + 2p + 1p
