Given that Joseph earns $15 for every lawn he mows.
so if he mows lown 1 time then his earning = $15
if he mows lown 2 time then his earning = $15*2= $30
if he mows lown 3 time then his earning = $15*3= $45
if he mows lown 4 time then his earning = $15*4= $60
if he mows lown 5 time then his earning = $15*5= $75
So the required table will be:
From the table we can see that Joseph's earning increases by $15 each time so we can say that YES, the amount of money he earns proportional to the number of lawns he mows.
Answer:
The expected participation rate is 0.637.
The standard error is 0.04397
Step-by-step explanation:
For each working age people asked, there are only two possible outcomes. Either they are in the labor force, or they are not. This means that we can solve this problem using binomial distribution probability concepts.
Binomial probability:
Expected value for the participation rate: The expected value is the probability of a success. In this problem, a success is a working age people being in the labor force. 63.7% of them are. So 
. This means that the expected participation rate is 0.637.
Standard error for the participation rate:
The standard error is given by the following formula:
.
In this problem, 120 people are asked, so 
.
So the standard error is 0.04397
(6 times 2x) + (6 times 5y)
A whole number that would support Cindys claim would be 2 because if u do the ,math it would be 8/24 which would be .333 repeating which is simplify to 1/3 and i do not know a number that would not work
<span>Because <span>t <span>is given in years and 1.08 <span>= <span>1 <span>+ <span>0.08, the annual percent increase
<span>is 8%.
To find the monthly percent increase that gives an 8% annual increase,
<span>use the fact that
t =
<span><span><span><span>
<span><span><span><span>and the properties of exponents to rewrite the
model in a form that reveals the monthly growth rate.</span></span></span>
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