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3 years ago

If 133mL of a 1.2 M glucose solution is diluted to 41.0L, what is the molarity of the diluted solution?

Chemistry

1 answer:

WITCHER [35]3 years ago

7 0

the formula we is as follows:-

M1V1= M2V2

where

M1=1.2

V1=0.133l

V2=41l

M2=?

1.2 × 0.133 = 41 × M2

0.1596 = 41 × M2

M2 = 0.15960/41

M2 = 0.0038926829

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2 years ago

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2 years ago

1.00 L of a gas at STP is compressed to 473mL. What is the new pressure of gas?

Ratling [72]

Hello!

1.00 L of a gas at STP is compressed to 473 mL. What is the new pressure of gas?

We have the following data:

Vo (initial volume) = 1.00 L

V (final volume) = 473 mL → 0.473 L

Po (initial pressure) = 1 atm (pressure exerted by the atmosphere - in STP)

P (final pressure) = ? (in atm)

We have an isothermal transformation, that is, its temperature remains constant, if the volume of the gas in the container decreases, so its pressure increases. Applying the data to the equation Boyle-Mariotte, we have:

$P_0*V_0 = P*V$

$1*1 = P*0.473$

$1 = 0.473\:P$

$0.473\:P = 1$

$P = \dfrac{1}{0.473}$

$\boxed{\boxed{P \approx 2.11\:atm}}\:\:\:\:\:\:\bf\green{\checkmark}$

Answer:

The new pressure of the gas is 2.11 atm

___________________________________

$\bf\blue{I\:Hope\:this\:helps,\:greetings ...\:Dexteright02!}\:\:\ddot{\smile}$

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2 years ago

In a given substance, as the temperature of a substance increases, the volume of that substance

steposvetlana [31]

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2 years ago

Hydrazine, N2H4, may react with oxygen to form nitrogen gas and water.

Sindrei [870]

Answer:

The percent yield of the reaction is 35 %

Explanation:

In the reaction, 1 mol of hydrazine reacts with 1 mol O₂ to produce 1 mol of nitrogen and 2 moles of water.

Let's verify the moles that were used in the reaction.

2.05 g . 1mol/ 32 g = 0.0640 mol

In the 100% yield, 1 mol of hydrazine produce 1 mol of N₂ so If I used 0.0640 moles of reactant, I made 0.0640 moles of products.

Let's use the Ideal Gases Law equation to find out the real moles of nitrogen, I made (real yield).

1atm . 0.550L = n . 0.082 . 295K

(1atm . 0.550L) / 0.082 . 295K = n → 0.0225 moles

Percent yield of reaction = (Real yield / Theoretical yield) . 100

(0.0225 / 0.0640) . 100 = 35%

3 0

2 years ago

Read 2 more answers