The third question requires you to solve for the weight of sodium (Na) and weight of Chloride (Cl) from the calculated moles of each element Na, and Cl.
So, you need to multiply the calculated moles of Na with its molar mass (23 g/ mol) to get the answer for Na. And multiply the calculated moles of Cl with its molar mass (35.45 g/mol) to get the answer for Cl.
The Kelvin Scale is used, so the answer is temperature :)
Answer:
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- <u>b. See the description below</u>
Explanation:
<u><em>a. Volume of 0.400 M CuSO₄(aq) required for the preparation</em></u>
In dissolutions, since the number of moles of solute is constant, the equation is:

Substitute and solve for V₁


<u><em>b. Briefly describe the essential steps to most accurately prepare the 0.150 M CuSO₄(aq) from the 0.400 M CuSO₄(aq)</em></u>
You will use the stock solution, the funnel, the buret, and distilled water.
i) Using the funnel, fill in the buret with with 50 ml of the stock solution, i.e. the 100. ml of 0.400 M CuSO₄(aq) solution.
ii) Pour 37.5 ml of the stock solution from the burete into the volumetric flask.
iii) Carefully add disitlled water to the 37.5ml of the stock solution in the volumetric flask until the mark (50 ml) on the volumetric flask.
iv) Put the stopper and rotate the volumetric flask to homegenize the solution.
P₁ = 0.90 atm
V₁ = 50.0 mL
T₁ = 298 K
P₂ = 1 atm
T₂ = 273 K
V₂ = P₁ x V₁ x T₂ / T₁ x P₂
V₂ = 0.90 x 50.0 x 273 / 298 x 1
V₂ = 12285 / 298
V₂ = 41 mL
Answer (1)
hope this helps!
3–ethyl–2,4–dimethylhexane
CH₃-CH(CH₃)-CH(C₂H₅)-CH(CH₃)-CH₂-CH₃