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3 years ago

What is the value of c? 56.70

Chemistry

1 answer:

Gennadij [26K]3 years ago

6 0

Due to the lack of information provided, the best I can give you is this:

In Chemistry, the letter c most commonly refers to specific heat, which is present in the ratio J/g°C.

Hope it helps :)

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Argue whether this chemical reaction supports or does not support the Law of Conservation of Matter.

Anit [1.1K]

Explanation:

The reaction is as follows:

2Mg(s) + O2(g) ---> 2MgO(s)

and the researcher said that 32 g of MgO was produced.

Stoichiometry:

28 g Mg × (1 mol Mg/24.305 g Mg) = 1.15 mol Mg

15 g O2 × (1 mol O2/15.999 g O2) = 0.938 mol O2

1.15 mol Mg × (2 mol MgO/2 mol MgO) = 1.15 mol MgO

1.15 mol MgO × (40.3044 g MgO/1 mol MgO) = 46.6 g MgO

0.938 mol O2 × (2 mol MgO/1 mol O2) = 1.88 mol MgO

1.88 mol MgO × (40.3044 g MgO/1 mol MgO = 75.6 g MgO

Based on these numbers, the amount of product after the reaction is much less than expected so these results don't seem to support the law of conservation of matter.

4 0

3 years ago

Titanium dioxide (TiO ) is used extensively as a white pigment. It is produced from an ore that contains ilmenite (FeTiO ) and f

rusak2 [61]

Answer:

= 7392 kg solution

Explanation:

detailed solving is given in the attached document.

5 0

3 years ago

When the process of condensation occurs, the kinetic energy of particles.

amm1812

Answer:

Is insufficient to overcome intermolecular forces.

Explanation:

Hope this helps

Please let me know if I'm wrong

5 0

2 years ago

A presión de 3atm, 7L de un gas a temperatura constante experimenta un cambio ocupando un volumen de 0,5L ¿Cuál será la presión

pantera1 [17]

Answer:

La presión que ejerce es 42 atm.

Explanation:

La ley de Boyle relaciona la presión y el volumen y dice que el volumen ocupado por una determinada masa gaseosa a temperatura constante, es inversamente proporcional a la presión.

La ley de Boyle se expresa matemáticamente como:

P*V=k

Ahora es posible suponer que tienes un cierto volumen de gas V1 que se encuentra a una presión P1 al comienzo del experimento. Si varias el volumen de gas hasta un nuevo valor V2, entonces la presión cambiará a P2, y se cumplirá:

P1*V1= P2*V2

En este caso:

P1= 3 atm
V1= 7 L
P2= ?
V2= 0.5 L

Reemplazando:

3 atm* 7 L= P2* 0.5 L

Resolviendo:

$P2=\frac{3 atm*7 L}{0.5 L}$

P2= 42 atm

<u><em>La presión que ejerce es 42 atm.</em></u>

3 0

3 years ago

A) What volume of butane (C 4 H 10 ) can be produced at STP, from the reaction of 13.45 g of carbon with 17.65 L of hydrogen gas

UNO [17]

From the stoichiometry of the reaction, carbon is in excess and 5.856 g s left over.

<h3>What is the volume of butane produced?</h3>

The reaction can be written as; 4C(s) + 5H2(g) -----> C4H10(g)

Number of moles of C = 13.45 g/1 2g/mol = 1.12 moles

If 1 mole of hydrogen occupies 22.4 L

x moles of hydrogen occupies 17.65 L

x = 0.79 moles

Now;

4 moles of carbon reacts with 5 moles of hydrogen

1.12 moles of carbon reacts with 1.12 moles * 5 moles/4 moles

= 1.4 moles of hydrogen

Hence hydrogen is the limiting reactant here and carbon is in excess.

If 4 moles of carbon reacts with 5 moles of hydrogen

x moles of carbon reacts with 0.79 moles of hydrogen

x = 0.632 moles

Number of moles of carbon unreacted = 1.12 moles - 0.632 moles

= 0.488 moles

Mass of carbon unreacted = 0.488 moles * 12 g/mol

= 5.856 g

Volume of butane produced is obtained from;

5 moles of hydrogen produces 1 mole of butane

0.79 moles of hydrogen produces 0.79 moles * 1 mole/ 5 moles

= 0.158 moles

1 mole of butane occupies 22.4 L

0.158 moles of butane occupies 0.158 moles * 22.4 L/ 1 mole

= 3.53 L

Learn more about stoichiometry:brainly.com/question/9743981

#SPJ1

5 0

2 years ago