Find the equation of the line that is parallel to y=3x-2 and contains the point (2,11).

Mathematics

1 answer:

SOVA2 [1]2 years ago

6 0

Answer:

y - 11 = 3 (x - 2)

Step-by-step explanation:

This is in point slope form, that is by far the best form to be in. Point slope form is best when there is a point and it gives it to you in slope intercept form. you take the slope from the original equation and stick it into y - (y point) = slope (x - (x point)) you know it is the right equation because it gives you the slope, which is the same, and the point, which is given.

The way to get it into slope intersept form you just solve for y

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A parallelogram with an area of 60 square units is formed by four lines in a coordinate plane. The parallelogram has one vertex

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Answer:

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Step-by-step explanation:

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2 years ago

Factor the GCF: −12x4y − 9x3y2 + 3x2y3

monitta

Factor the coefficients:
-12=(-1)(3)(2^2)
-9=(-1)(3^2)
3=3

The greatest common factor (GCF) is 3

Next we find the GCF for the variable x.
x^4
x^3
x^2
The GCF is x^2.

Next GCF for variable y.
y
y^2
y^3
the GCF is y

Therefore the GCF is 3x^2y
To factor this out, we need to divide each term by the GCF,
(3x^2y)(−12x4y/(3x^2y) − 9x3y2/(3x^2y) + 3x2y3/(3x^2y) )
=(3x^2y)(-4x^2-3xy+y^2)
if we wish, we can factor further:
(3x^2y)(y-4x)(x+y)

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2 years ago

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tamaranim1 [39]

Answer:

Step-by-step explanation:

Hoped this helped!

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