Answer:
i want to see the choices
Answer:
C
Step-by-step explanation:
C
Answer:
The third quartile is:
Step-by-step explanation:
First organize the data from lowest to highest
4, 5, 10, 12, 14, 16, 18, 20, 21, 21, 22, 22, 24, 26, 29, 29, 33, 34, 43, 44
Notice that we have a quantity of n = 20 data
Use the following formula to calculate the third quartile 
For a set of n data organized in the form:
The third quartile is :
With n=20
The third quartile is between 
and 
Then
Answer:
Step-by-step explanation:
The shape consists of three parts: a half sphere, a round cylinder and a round cone.
The half sphere volume = 1/2 * 4/3 * π * (4)^3
= 32/3 π
The round cyllinder volume = π * (4)^2 * 10
= 160 π
The round cone volume = 1/3 * π * (4)^2 * 3
= 16 π
Adding them together, the volume of shape
= 32/3 π + 160π + 16π
= (32/3 + 160 + 16)*3.14
= 586.13
Similarly the surface area
= (4π4^2)/2 + 2π4*10 + π*4*5
= (32+80+25)*3.14
= 430.18
Imx->0 (asin2x + b log(cosx))/x4 = 1/2 [0/0 form] ,applying L'Hospital rule ,we get
= > limx->0 (2a*sinx*cosx - (b /cosx)*sinx)/ 4x3 = 1/2 => limx->0 (a*sin2x - b*tanx)/ 4x3 = 1/2 [0/0 form],
applying L'Hospital rule again ,we get,
= > limx->0 (2a*cos2x - b*sec2x) / 12x2 = 1/2
For above limit to exist,Numerator must be zero so that we get [0/0 form] & we can further proceed.
Hence 2a - b =0 => 2a = b ------(A)
limx->0 (b*cos2x - b*sec2x) / 12x2 = 1/2 [0/0 form], applying L'Hospital rule again ,we get,
= > limx->0 b*(-2sin2x - 2secx*secx.tanx) / 24x = 1/2 => limx->0 2b*[-sin2x - (1+tan2x)tanx] / 24x = 1/2
[0/0 form], applying L'Hospital rule again ,we get,
limx->0 2b*[-2cos2x - (sec2x+3tan2x*sec2x)] / 24 = 1/2 = > 2b[-2 -1] / 24 = 1/2 => -6b/24 = 1/2 => b = -2
from (A), we have , 2a = b => 2a = -2 => a = -1
Hence a =-1 & b = -2
