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Mashutka [201]
3 years ago
14

Find the equation of the line that is parallel to y=3x-2 and contains the point (2,11).

Mathematics
1 answer:
SOVA2 [1]3 years ago
6 0

Answer:

y - 11 = 3 (x - 2)

Step-by-step explanation:

This is in point slope form, that is by far the best form to be in. Point slope form is best when there is a point and it gives it to you in slope intercept form. you take the slope from the original equation and stick it into y - (y point) = slope (x - (x point)) you know it is the right equation because it gives you the slope, which is the same, and the point, which is given.

The way to get it into slope intersept form you just solve for y

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the area of a square is A = s^2, where s is the length of one side of the square. what is the side length s for each square ? th
vlada-n [284]

Answer:

18

Step-by-step explanation:

324 = s^2 -->

sqrt324 = s -->

sqrt(2^2 * 9^2) = s -->

2*9 = s -->

18 = s

5 0
3 years ago
Graph the function 2 3^sqrt x+2 +4​
Ghella [55]

Answer: b; y intercept between 8 and 4

Step-by-step explanation:

1. a; 2/3

2. b; 3, all real numbers except x=2

3. a; $.75

4. c; intercepting at (-3,-3)

5. b; 5

6. a; starts at 3

7. b; 1975

8. b; y intercept between 8 and 4

8 0
3 years ago
Can someone help me shot this problem
bearhunter [10]

Answer:

A) sin θ = 3/5

B) tan θ = 3/4

C) csc θ = 5/3

D) sec θ = 5/4

E) cot θ = 4/3

Step-by-step explanation:

We are told that cos θ = 4/5

That θ is the acute angle of a right angle triangle.

To find the remaining trigonometric functions for angle θ, we need to find the 3rd side of the triangle.

Now, the identity cos θ means adjacent/hypotenuse.

Thus, adjacent side = 4

Hypotenuse = 5

Using pythagoras theorem, we can find the third side which is called opposite;

Opposite = √(5² - 4²)

Opposite = √(25 - 16)

Opposite = √9

Opposite = 3

A) sin θ

Trigonometric ratio for sin θ is opposite/hypotenuse. Thus;

sin θ = 3/5

B) tan θ

Trigonometric ratio for tan θ is opposite/adjacent. Thus;

tan θ = 3/4

C) csc θ

Trigonometric ratio for csc θ is 1/sin θ. Thus;

csc θ = 1/(3/5)

csc θ = 5/3

D) sec θ

Trigonometric ratio for sec θ is 1/cos θ. Thus;

sec θ = 1/(4/5)

sec θ = 5/4

E) cot θ

Trigonometric ratio for cot θ is 1/tan θ. Thus;

cot θ = 1/(3/4)

cot θ = 4/3

5 0
3 years ago
Can any one help me
emmainna [20.7K]
I think you set up the equation like this

$2.50x+5

I hope I helped sorry if I didn't.

8 0
3 years ago
What is the answer?How do you solve this?
Alika [10]

Answer:

you have to look at the chart and use the chart to answer the questions at the botttom

Step-by-step explanation:

4 0
3 years ago
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